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My name is Ann [436]
3 years ago
6

1. What is the magnitude of the force on a charge of +40 μC that is 0.6 m from a charge of - 80 μC?

Physics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

The magnitude of the force is 79.893 N.

Explanation:

The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}} (1)

Where:

\kappa - Electrostatic constant, in newtons-square meters per square coulomb.

q_{A}, q_{B} - Electric charges, in coulombs.

r - Distance, in meters.

If we know that \kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, q_{A} = +40\times 10^{-6}\, C, q_{B} = - 80\times 10^{-6}\, C and r = 0.6\,m, then the magnitude of the force is:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}

F = 79.893\,N

The magnitude of the force is 79.893 N.

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