Answer:
d₁ = 0.29 in
d₂ = 0.505 in
Explanation:
Given:
T = 1500 lbf in
L = 10 in
x = 0.5 L = 5 in

First case: T = T₁ + T₂
T₂ = T - T₁ = 1500 - 750 = 750 lbf in
If the shafts are in series:
θ = θ₁ + θ₂
θ = ((T₁ * L₁)/GJ) + ((T₂ * L₂)/GJ)
Second case: If d₁ ≠ d₂
θ = ((T₁ * L₁)/GJ₁) + ((T₂ * L₂)/GJ₂) = 0 (eq. 1)
t₁ = t₂
(eq. 2)
T₁ + T₂ = 1500 (eq. 3)
θ₁ first case = θ₁ second case
Replacing:

The same way to θ₂:

From equation 2, we have:
d₁ = 0.587 * d₂
From equation 3, we have:
d₂ = 0.505 in
d₁ = 0.29 in
Answer:
it can be called PE or sometimes, there are equations which you can use the letter U.
Explanation:
Mass of Tracey M1 = 32 kg
Mass of Jonas M2 = 45 kg
Initially both were at rest
so V1i = V2i =0
after pushing each other Jonas speed V2f = 0.80 m/s
we need to find out final speed of Tracy
Here we can use momentum conservation as no external force is acting here
M1V1i + M2V2i = M1V1f + M2V2f
32(0) + 45(0) = 32 V1f + 45(0.80)
0 = 32 V1f + 36
-36 = 32 V1f
V1f = - 1.125 m/s
negative sign shows that Tracy will move opposite to the Jonas
so answer in two significant figure would be
V1f = 1.1 m/s
<span> Balanced. If not so, then the car cannot move with uniform speed. The frictional force is balanced by the force exerted by the engine. </span>