A bowler who always left the same 3 pins standing could be considered a C. Precise bowler as from bowling countless number of times he has observed the same amount of pins knocked down each time.
Answer: C
Frictional force
Explanation:
The description of the question above is an example of a circular motion.
For a car travelling in a curved path, the frictional force between the tyres and the road surface will provide the centripetal force.
Since the road is banked, and the cross section of the banked road is constructed like a ramp. The car drives transversely to the slope of the ramp, so that the wheels of one side of the car are lower than the wheels on the other side of the car, for cornering the banked road, the car will not rely only on the frictional force.
Therefore, the correct answer is option C - the frictional force.
Hi there!
Great question!
Basketballs have air inside them. A special pump is used to insert the air. That's why you can lift the basketballs off the ground easily. If it was a solid, though, you'd hardly be able to lift the ball up! Basketballs can float, too, because anything with air inside can float. If it were solid, it would sink in the water easily.
Hope this helps! :D
Answer:
"8 units" is the appropriate answer.
Explanation:
According to the question,
Throughout equilibrium all particles are of equivalent intensity, and as such the integrated platform's total energy has been uniformly divided across all individuals.
Now,
The total energy will be:
= ![480+720](https://tex.z-dn.net/?f=480%2B720)
= ![1200 \ units](https://tex.z-dn.net/?f=1200%20%5C%20units)
The total number of particles will be:
= ![50+100](https://tex.z-dn.net/?f=50%2B100)
= ![150](https://tex.z-dn.net/?f=150)
hence,
Energy of each A particle or each B particle will be:
= ![\frac{1200}{150}](https://tex.z-dn.net/?f=%5Cfrac%7B1200%7D%7B150%7D)
= ![8 \ units](https://tex.z-dn.net/?f=8%20%5C%20units)
Answer:
0.015![meter^{2}](https://tex.z-dn.net/?f=meter%5E%7B2%7D)
Explanation:
Total volume of water coming out = 1.33![meter^{3}](https://tex.z-dn.net/?f=meter%5E%7B3%7D)
Also volume = Cross sectional area*Length covered
Length covered = Velocity *time
=24.5*3.55
=86.97 meter
Let the cross sectional area be A.
1.33 = 86.97*A
A =0.015![meter^{2}](https://tex.z-dn.net/?f=meter%5E%7B2%7D)