Answer:
11.9 g of nitrogen monoxide
Explanation:
We'll begin by calculating the number of mole in 6.75 g of NH₃. This can be obtained as follow:
Mass of NH₃ = 6.75 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 6.75 / 17
Mole of NH₃ = 0.397 mole
Next, we shall determine the number of mole of NO produced by the reaction of 0.397 mole of NH₃. This can be obtained as follow:
4NH₃ + 5O₂ —> 4NO + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Therefore, 0.397 mole of NH₃ will also react to produce 0.397 mole of NO.
Finally, we shall determine the mass of 0.397 mole of NO. This can be obtained as follow:
Mole of NO = 0.397 mole
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO =?
Mass = mole × molar mass
Mass of NO = 0.397 × 30
Mass of NO = 11.9 g
Thus, the mass of NO produced is 11.9 g
Answer:
An ionic bond is the bonding between a non-metal and a metal, that occurs when charged atoms (ions) attract.
Explanation:
Here I put the function of Iconic Bond.
- <em>Ionic bonds form so that the outermost energy level of atoms are filled. Ion. an atom or group of atoms that bring out a positive or negative electric charge as a result of having lost or gained one or more electrons.</em>
<em>Therefore, I hope this helps!</em>
Answer:
We assume you are converting between moles CO2 and gram. You can view more details on each measurement unit: molecular weight of CO2 or grams This compound is also known as Carbon Dioxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CO2, or 44.0095 grams.
Sodium is a metal, Chloride is a non-metal.
Right off the bat, you know that in order for both of these atoms to achieve a full valence shell that the metal has to lose electrons, and the non-metal has to gain them.
Therefore, you have the transfer of electrons in this bond in order to form ions.
Na+ and Cl-. This transfer of electrons in a bond is called an {{ Ionic Bond}}
<span>2H2 + O2 → 2H2O</span>
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<span>okay???</span>
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