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antoniya [11.8K]
3 years ago
8

When potassium bromate (kbro3 ) is heated, it decomposes into potassium bromide and a gas that supports the combustion of a glow

ing splint?
Chemistry
1 answer:
Tom [10]3 years ago
6 0

We know that the oxygen (O2) causes a glowing splint to reignite, however, let us check what is missing on the products side of the chemical equation: <span>
KBrO3 → KBr + ? 
As we see, oxygen (O2) is the element missing from the other side. Therefore the balanced chemical equation for this decomposition is as follows: </span>
<span>2KBrO3 → 2KBr + 3O2 </span>

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Which substance is the reducing agent in this reaction? 16h++2cr2o72−+c2h5oh→4cr3++11h2o+2co2 express your answer as a chemical
lana66690 [7]

16 H + + 2Cr2O72- + C2H5OH → 4 Cr3 + +11H2O +2CO2

The reducing agent is C2H5OH

Explanation

reducing  agent is a substance that loses or donate electrons  in a chemical reaction. C2H5OH is the one which donate electrons in the above chemical equation.

7 0
3 years ago
If electromagnetic radiation has a frequency of 2.0×1015s−1, what is the radiation’s energy?(1 point)
Alika [10]
  • Frequency=v=2×10^15Hz
  • Energy=E

Using planks quantum theory

\\ \sf\longmapsto E=hv

\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 2\times 10^{15}s^{-1}

\\ \sf\longmapsto E=13.252\times 10^{-19}J

\\ \sf\longmapsto E=1.3\times 10^{-18}J

7 0
3 years ago
3. A helium laser emits light with a wavelength of 6.33 x 10^-7m. What is
HACTEHA [7]

Answer:

4.52 x 10¹⁴ cycles/s

Explanation:

From c = f·λ => f = c/λ = (3.0 x 10⁸ m/s)/(6.63 x 10⁻⁷m) = 4.52 x 10¹⁴ cycles/s.

f = frequency = ?

λ = wavelength = 6.63 x 10⁻⁷ meter

c = speed of light in vacuum = 3.0 x 10⁸ meters/s

7 0
2 years ago
Be sure to answer all parts. For the complete redox reactions given here, write the half-reactions and identify the oxidizing an
OlgaM077 [116]

Answer : O_2 is the oxidizing agent and Fe is the reducing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

4Fe+3O_2\rightarrow 2Fe_2O_3

The half oxidation-reduction reactions are:

Oxidation reaction : Fe\rightarrow Fe^{3+}+3e^-

Reduction reaction : O_2+4e^-\rightarrow 2O^{2-}

In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.

Oxidation reaction : 4Fe\rightarrow 4Fe^{3+}+12e^-

Reduction reaction : 3O_2+12e^-\rightarrow 6O^{2-}

4Fe+3O_2\rightarrow 2Fe_2O_3

In this reaction, 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'O_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, O_2 is the oxidizing agent and Fe is the reducing agent.

7 0
3 years ago
The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.
hoa [83]

The actual yield is 43 g Cl₂.

The <em>limiting reactant was MnO₂</em> because it gave the smaller mass of Cl₂.

∴ The <em>theoretical yield</em> is 60.25 g Cl₂.

% yield = actual yield/theoretical yield × 100 %

Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g

8 0
3 years ago
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