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alex41 [277]
3 years ago
15

Pls answer ill give brainliest question in picture

Chemistry
1 answer:
satela [25.4K]3 years ago
3 0

Answer: A & D

Explanation:

The two main forces are temperature and salinity.

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The water cycle is also known as the _______ cycle?
valina [46]

Answer:

hydrological cycle

Explanation:

water cycle is also known as hydrological vycle

4 0
3 years ago
Read 2 more answers
The table shows the amount of radioactive element remaining in a sample over a period of time.
Lunna [17]

Answer:

1. The half-life is 22 years.

2. 132 years

Explanation:

1. Determination of the the half-life.

The half-life of an element is the time taken for half the element to decay.

From the table given above, the original amount of the element 45 g. If we divide 45 by 2, we'll have 22.5 g as half the original amount of element.

Now, the time taken to obtain 22.5 g as shown from the table is 22 years.

Thus, the half-life the element is 22 years.

2. Determination of the time.

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Time (t) =?

Next, we shall the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

4.8125 = 1/2ⁿ × 308

Cross multiply

4.8125 × 2ⁿ = 308

Divide both side by 4.8125

2ⁿ = 308 / 4.8125

2ⁿ = 64

Express 64 in index form with 2 as the base.

2ⁿ = 2⁶

n = 6

Thus, 6 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Number of half-lives (n) = 6

Half-life (t½) = 22 years

Time (t) =?

n = t / t½

6= t / 22 years

Cross multiply

t = 6 ×22

t = 132 years.

Thus, the time taken is 132 years.

6 0
3 years ago
If the absorbance at 555nm wavelength of a 0.35 moles/liter sample of stained protein has an absorbance of 0.12, what is the con
inna [77]
At 0.35 M Absorbance = 0.12

Use Given to
5 0
3 years ago
All of the following are physical properties except _____.
cricket20 [7]
Reactivity with oxygen
5 0
3 years ago
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Consider a sample of calcium carbonate in the form of a cube measuring 2.805 in. on each edge.
Naya [18.7K]

Answer:

The answer to your question is: 8.82 x 10 ²⁴ atoms of oxygen          

Explanation:

Data

Cube measuring : 2.805in on each edge

density = 2.7 g/cm3

# of oxygen atoms in the cube = ?

Process

Volume of the cube = (2.805)³ = 22.07 in³

Convert in³ to cm³                  1 in³   -------------------  16.39 cm³

                                       22.07 in³    --------------------    x

                        x = (22.07 x 16.39) / 1 = 361.72 cm³

Density = mass / volume

Mass = density x volume

Mass = (2.7)(361.72) = 976.66 g

Atomic mass CaCO3 = 40 + 12 + (16 x 3) = 100 g

                                100 g of CaCO3 --------------------  48 g of O2

                                976.66 g of CaCO3 ---------------    x

                           x = (976.66 x 48) / 100 = 468.8 g of O2

                              32 g of O2 ----------------------  1 mol

                           468.8 g of O2 --------------------   x

                       x = (468.8 x 1) / 32 = 14.65 mol

                           1 mol -----------------------   6.023 x 10 ²³ atoms

                        14.65 mol -------------------    x

                    x = (14.65 x 6.023 x 10 ²³) / 1 = 8.82 x 10 ²⁴ atoms of oxygen          

3 0
3 years ago
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