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goblinko [34]
2 years ago
5

Find the slope of the graph

Mathematics
1 answer:
notka56 [123]2 years ago
7 0

Answer:

No image please add it on your next question.

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gogolik [260]

Answer:

.................................................................................

........................

Step-by-step explanation:

Please MARK AS BRAINLIEST

4 0
3 years ago
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
2 years ago
Find the midpoint and distance on a number line between 6, -15
SCORPION-xisa [38]
So it is distance from zero so 6+15=21

1 2 3 4 5 6 7 8 9 10 (11) 12 13 14 15 16 17 18 19 20 21
eliminate one from each side till you find the middle
7 0
3 years ago
Please help asap!!!!
Triss [41]

Answer: B

Step-by-step explanation: The answer would be B because you would add n the number and 6 then you would multiply it by 2

5 0
3 years ago
Will somebody please answer this question? I'm stuck and in a bit of a hurry. A surfboard shaper has to limit the cost of develo
ikadub [295]

Answer:

  ≥ 420 boards

Step-by-step explanation:

Write the required relation between cost per board and "x" (the number of boards that must be sold).

  143 + 30240/x ≤ 215 . . . . . . . note that the first term is <em>not</em> 143x

Subtract 143

  30240/x ≤ 72

Multiply by x/72. This is a positive number because x is a positive number.

  30240/72 ≤ x

  420 ≤ x

At least 420 surfboards must be sold to limit the final cost per board to $215.

8 0
3 years ago
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