Question

What is the molecular formula for a compound with an empirical formula of CH₃O and a molar mass of 62g?

Answer 1

Answer:

$CH_{6} O_{2}$

Explanation:

Molecular formula can be calculated by finding the ratio of the molecular molar mass to the empirical molar mass, then multiplying the subscripts of the empirical molar mass by that ratio.

The empirical molar mass is 12.01 + 3(1.01) + 16.00 = 31.04g

The molecular molar mass is 62g

62/31.04 = 2

So the molecular formula is $CH_{6} O_{2}$