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Ann [662]
3 years ago
15

What is your hypothesis (or hypotheses) for this experiment? (Lab was on Newton’s first two laws of motion)

Physics
2 answers:
Shalnov [3]3 years ago
7 0
My hypothesis is the water would change color and starts to boil or it could be an experiment that may glow up in the dark.
patriot [66]3 years ago
3 0

Answer:

it was about geting

Explanation:

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Simple physics question, check the document. Should take about 3-5 minutes.
Ahat [919]

Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N

5 0
3 years ago
Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwin
DedPeter [7]

Answer:

Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.

The net recoil velocity must be zero.

8 0
3 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
You should be extra careful during the hours of sunrise, sunset, and nighttime because
skelet666 [1.2K]

Poor visibility, difficulties in colour perception, lessened colour contrast vision due to darker shadows and reduced peripheral vision, these are the reasons why one has to be extra careful while driving during hours of sunrise, sunset and night time.  

<h3><u> Explanation: </u></h3>

Sunrise, sunset and night time are parts of the day with minimal or absolutely no presence of sunlight. To safely navigate roads, we require enough light in order to detect presence of other vehicles, signs and pedestrians. Less sunlight during sunrise and sunset light the sky but makes the roads and vehicles have a darker, less bright view. The contrast between colours is the least, making it difficult to identify objects and see clearly.  

A rising or a setting sun can also lead to glares on the driver’s view and thus obstruct it. Since a change in ambient light is observed, our eyes need to adjust with this change and this isn’t spontaneous. Night time driving has headlight glares from approaching vehicles and reduced surrounding visibility. The eyes switching for vision adaptability from dark to bright light if vehicles approach and pass by is not a quick action. Hence the driver’s vision is compromised in every such case and this may lead to accidents.  

7 0
4 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
drek231 [11]

Answer:

5 mm

Explanation:

Youngs's modulus (Y) is described by the following expression:

Y=\frac{F*L}{\Delta L*A}

Where F is the force exerted on the tendon, L is its length, A is its area and ΔL is its change in length (stretching).

The force in this case is 8 times the weight of the runner:

F= 8*m*g\\F= 8*70*9.8\\F=5488 N

Therefore, the change in length of the tendon is given by:

\Delta L=\frac{F*L}{Y*A}\\\Delta L=\frac{5488*0.15}{0.15*10^{10}*1.1*10^{-4}}\\\Delta L= 0.004989 m

the runner's Achilles tendon will stretch by 0.004989 m, which is roughly 5 mm.

8 0
4 years ago
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