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babymother [125]
3 years ago
9

You should be extra careful during the hours of sunrise, sunset, and nighttime because

Physics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Poor visibility, difficulties in colour perception, lessened colour contrast vision due to darker shadows and reduced peripheral vision, these are the reasons why one has to be extra careful while driving during hours of sunrise, sunset and night time.  

<h3><u> Explanation: </u></h3>

Sunrise, sunset and night time are parts of the day with minimal or absolutely no presence of sunlight. To safely navigate roads, we require enough light in order to detect presence of other vehicles, signs and pedestrians. Less sunlight during sunrise and sunset light the sky but makes the roads and vehicles have a darker, less bright view. The contrast between colours is the least, making it difficult to identify objects and see clearly.  

A rising or a setting sun can also lead to glares on the driver’s view and thus obstruct it. Since a change in ambient light is observed, our eyes need to adjust with this change and this isn’t spontaneous. Night time driving has headlight glares from approaching vehicles and reduced surrounding visibility. The eyes switching for vision adaptability from dark to bright light if vehicles approach and pass by is not a quick action. Hence the driver’s vision is compromised in every such case and this may lead to accidents.  

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A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed
sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

Fd = \frac{1}{2} m (v_i^2- v_f^2)

where,

v_f = 0

F = u_kmg

(\mu_kg) d = \frac{1}{2} m v_i^2

d = \frac{\frac{1}{2}v_i^2}{\mu_kg}

d = \frac{v_i^2}{2 \mu_kg}

b. The initial speed of the carton if the factor of 3 risen, so the expression is

v_i^1 = 3v_i

d^i = \frac{(3v_i^2)}{2\mu_kg}

= \frac{9v_i^2}{2\mu_kg}

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8 0
3 years ago
You are driving due north on i-81 to come to jmu with a speed of 10 m/s, suddenly you realize you forgot your book. You make a u
Readme [11.4K]

first we make a U turn and travel towards home in t = 20 s

so the distance of home from initial position is

d_1 = v*t_1

d_1 = 10*20 = 200 m

Now after picking up the book we travel back with speed 20 m/s

so again after t = 20 s the displacement is given as

d_2 = v*t = 20*20 = 400 m

so the net displacement is given as

\vec d = \vec d_2 - \vec d_1

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8 0
3 years ago
Light is shining perpendicularly on the surface of the earth with an intensity of 680 W/m^2. Assuming that all the photons in th
andrew11 [14]

Answer:

3.066×10^21  photons/(s.m^2)

Explanation:

The power per area is:

Power/A = (# of photons /t /A)×(energy / photon)

E/photons = h×c/(λ)

photons /t /A = (Power/A)×λ /(h×c)  

photons /t /A = (P/A)×λ/(hc)

photons /t /A = (680)×(678×10^-9)/(6.63×10^-34)×(3×10^-8)

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Therefore, the number of photons per second per square meter 3.066×10^21  photons/(s.m^2).

4 0
3 years ago
What are the main activities involved in studying physics?
Firlakuza [10]
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7 0
3 years ago
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Kipish [7]

Answer:

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Explanation:

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7 0
2 years ago
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