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ss7ja [257]
3 years ago
10

An astronaut weighs 160 Newtons on the surface of of the moon where the acceleration due to gravity is 1.6 m/s/s. What is his we

ight on EARTH, where the acceleration due to gravity is 10 m/s/s? Include units in your answer. *
Physics
1 answer:
gladu [14]3 years ago
3 0

Answer:

The weight of an object with mass M, in a place with gravitational acceleration G, is:

W = M*G

We know that in the moon, with G = 1.6 m/s^2, the weight is 160N

Then we have the equation:

160N = (1.6 m/s^2)*M

With this, we can find the mass of the astronaut.

(160N)/(1.6 m/s^2) = M = 100kg.

Then in the Earth, where the acceleration is G = 10 m/s^2, the weight will be:

W = (10m/s^2)*100kg = 1000 N

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Answer it will move slower:

Explanation: cause the force that’s opposite of it

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The force between two magnetic poles varies directly with the distance of separation. True False
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This is true because they are the same type of pole.

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A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

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  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
4 years ago
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Answer:

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6 0
3 years ago
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a piece of clay with mass m is traveling with an unknown velocity in the positive x-direction, when it collides and sticks to a
joja [24]

Answer:

13 m in the + x direction.

Explanation:

Givens

m1 = m

m2 = 3m

v1= ? = x

v2 = - 3 m/s

v3 = v4 = - 1 m/s

Equation

Let x be the speed of the lighter object before collision.

Momentum before collision = momentum after collision

Solution

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m(x - 3*3m/s) = (m + 3m)(-1)

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7 0
3 years ago
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