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stich3 [128]
3 years ago
11

If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar

e true?
a. The angular frequency is doubled.
b. The amplitude is doubled.
c. The period is doubled.
d. The angular frequency is reduced to one-half of what it was.
e. The period is reduced to one-half of what it was.
Physics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}

when the frequency is doubled

\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1

Thus, the angular frequency will be doubled.

Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}

when the frequency is doubled;

T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}

Thus, the period will be reduced to one-half of what it was.

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Answer:

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Explanation:

Given

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Force sensor reading to which spring is attached , F=4.8\, N

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3 years ago
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Rashid [163]
<h2>Option 1 is the correct answer.</h2>

Explanation:

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We need to find energy,

Substituting

                 \texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}\\\\1790=\frac{\texttt{Energy}}{24\times 3600}

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Answers:

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