Answer:
If child weight is equal to rope force then child will move with uniform speed
or we can say that the child will remain at rest in his position
Explanation:
As we know that child is hanging by rope
so here there will be two forces on the child
1) Weight or gravitational force which act vertically downwards
2) Tension in the rope which act vertically upwards
Now if child will accelerate upwards then tension force must be more than the weight of the child
If tension force is less than the weight then child will decelerate and his speed will decrease
if tension force is equal to child weight then in that case the child will remain at rest or it will move with same speed
They farmed it and got rid of most of the buffalo. They also caused the locust plague from turning up the eggs in the dirt when it was first plowed.
Answer:
a=0.555m/s^2
Explanation:
First we find the distance traveled from the moment the engineer reacts to the car, assuming uniform movement
X=VT
X=(18)(0.45)=8.1m
then we find the distance at which the deceleration begins, which is obtained by subtracting the total distance with the inner result
X=300-8.1=291.9
finally we use the equation for constant acceleration
Vf=0 final speed
Vo=18m/s= initial speed
X=291.9m
(Vf^2-Vo^2)/2X=a
(0-18^2)/(2*291.9)=a
a=0.555m/s^2
