First, we have a change in the velocity from 85 to 164 m/s in 10 sec.
Then, we calculate the <u>acceleration </u>as:

Hence we need to calculate the velocity of the space vehicle at t = 2 sec using the first equation of motion:

Then, using the second equation of motion to calculate the distance:


The kinetic energy before equals K after
Answer:
The ocean is 6485.6m deep when measured from the vessel
Explanation:
v=1474m/s
t=8.88s
let d represent distance from the vessel to the ocean bottom.
an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.


d= 6485.6m
Answer:
A. Sulfur _________ group 16 chalcogens
B. Sodium _________ group 1 alkali metals
C. Argon _________ group 18 noble gases
D. Silicon _________ group 14 carbon family
E. Chlorine _________ group 17 halogens
F. Phosphorus_________ group 15 pnicogens
Answer:


Explanation:
See attachment for complete work.