A spring with a mass of 5 Kg has natural length 0.5m. A force of 35.6 N is required to maintain it stretched to a length of 0.5m
1 answer:
Answer:
Explanation:
force constant of spring k = force / extension
= 35.6 / 0.5
k = 71.2 N / m
angular frequency ω of oscillation by spring mass system
where m is mass of the body attached with spring
Putting the values
ω = 3.77 radian / s
The oscillation of the mass will be like SHM having amplitude of 0.5 m and angular frequency of 3.77 radian /s . Initial phase will be π / 2
so the equation for displacement from equilibrium position that is middle point can be given as follows
x = .5 sin ( ω t + π / 2 )
= 0.5 cos ω t
= 0.5 cos 3.77 t .
x = 0.5 cos 3.77 t .
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<h2>Answer: its temperature must increase.</h2>
Explanation:
In an isobaric process the pressure remains constant, which means the initial pressure and the final pressure will be the same.
In addition, during this thermodynamic process, the volume of the ideal gas expands or contracts in such a way that the variation of pressure is neutralized.
Now, according to the First law of Thermodynamics that establishes the conservation of energy:
(1)
Where:
is the internal energy
is the heat transferred
is the work
Now, for an isobaric process:
(2)
Where:
is the pressure (<u>always positive</u>)
is the volume variation of the gas
<u />
<u>Here we have two possible results:</u>
-If the gas expands (positive ), the work is positive.
-If the gas compresses (negative ), the work is negative.
In this case we are talking about the first result (work is positive).
Then, according to the above, equation (1) can be written as follows:
(3)
Clearing :
(4)
Then, for an ideal gas in an isobaric process, part of the heat () added to the system will be used to do work (positive in this case) and the other part <u>will increase the internal energy</u>, hence <u>the temperature will increase as well.</u>