Answer : The concentration of
ion, pH and pOH of solution is,
, 1.05 and 12.95 respectively.
Explanation : Given,
Concentration of
ion = 0.090 M
pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.
The expression used for pH is:
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
First we have to calculate the pH.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)


The pH of the solution is, 1.05
Now we have to calculate the pOH.

The pOH of the solution is, 12.95
Now we have to calculate the
concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![12.95=-\log [OH^-]](https://tex.z-dn.net/?f=12.95%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.12\times 10^{-13}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.12%5Ctimes%2010%5E%7B-13%7DM)
The
concentration is, 
Answer: the following are essential factors to be considered when choosing a solvent for crystallization
1. The crystallization solvent should not dissolve the substance to be purified at room temperature, but it should dissolve it well at the solvent’s boiling point
2. The solvent should dissolve soluble impurities well at room temperature.
3. The solvent should not dissolve insoluble impurities even at the solvent’s boiling
point.
4. The solvent must not react with the substance to be purified .
Answer:
pH = -log(concentration of hydro.gen ion)
1. When con. of H ion is 1*10-4 mol/L
pH = -log(1*10-4) = -(-4) = 4
2. A solution with a pH of 1*10-12mol/L
pH = -log (1*10-12) = -(-12) = 12
The pH is 12 and the solution is basic or alkaline
3.A solution with a pH of 6 has the concentration of
pH = -log (H+)
(H+) = arc log -pH
(H+) = 1*10-6
Explanation:
Answer:
see below
Explanation:
3. 87.073 meters to three significant figures.
= 87.1 meters
2. Write the number in scientific notation. _____meters
= 8.71 x 10 ¹ meters
Answer:
It is A).
Explanation:
Silver (Ag) goes from the pure metal to Ag+ losing 1 electron so it is oxidised.
The hydrogen ion gains electrons and is reduced.