Answer:
magnesium
Explanation:
it has a greater period number
Answer:
![[SO_2Cl_2]_{600}= 0.0842 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D_%7B600%7D%3D%200.0842%20M)
Explanation:
Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to 
.
The linear equation has the following terms:
It is a linear form of the integrated first-order law equation:
![ln[SO_2Cl_2]_t = -kt + ln[SO_2Cl_2]_o](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_t%20%3D%20-kt%20%2B%20ln%5BSO_2Cl_2%5D_o)
Therefore, the rate constant, k, is:
The natural logarithm of initial molarity is:
![ln[SO_2Cl_2]_o = -2.30](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_o%20%3D%20-2.30)
Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:
![ln[SO_2Cl_2]_{600} = -0.000290 s^{-1}\cdot 600 s - 2.30 = -2.474](https://tex.z-dn.net/?f=ln%5BSO_2Cl_2%5D_%7B600%7D%20%3D%20-0.000290%20s%5E%7B-1%7D%5Ccdot%20600%20s%20-%202.30%20%3D%20-2.474)
Take the antilog of both sides to find the actual molarity:
![[SO_2Cl_2]_{600}=e^{-2.474} = 0.0842 M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D_%7B600%7D%3De%5E%7B-2.474%7D%20%3D%200.0842%20M)
D. All of the answers are true
<span> The body has to do this to make sure and or to prevent damage to the delicate tissues that form the Respiratory System. This is important because </span>Your body's organs, such as your heart and brain, need oxygen-rich blood to work well. (if it gets damaged by the Cold/Dry air you breath in on a daily)<span><span>Respiratory failure </span>also can occur if
your lungs can't properly remove carbon dioxide (a waste gas) from your
blood. Too much carbon dioxide in your blood can harm your body's
organs.
Hopefully i helped ^.^ please mark brainly if its a possibility~
</span>
Answer:
C.) HOCl Ka=3.5x10^-8
Explanation:
In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below
we Know that
pKa= -log(Ka)
therefore
A) pKa of HClO2 = -log(1.2 x 10^-2)
=1.9208
B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644
C) pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45
D) pKa of HCN = -log(4 x 1 0^-10)= 9.3979
If we consider the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution
The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.
So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.
Hence, HOCl will be chosen for buffer construction.
