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joja [24]
3 years ago
13

Which of the following is a true statement about science?

Chemistry
2 answers:
masya89 [10]3 years ago
7 0
D. all of these are true statements
Papessa [141]3 years ago
4 0
D. All of the answers are true
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Given the heat change per mole for the combustion of methanol (-726 kJ/mol), predict the heat change that would occur if 0.200 m
DochEvi [55]

Answer:

-145.2kJ

Explanation:

Enthalpy is an extensive property as its value depends on the amount of substance present in the system.

If the enthalpy for one mole of methanol = -726 kJ/mol;

The Enthalpy for 0.2 mol is given as;

Enthalpy = 0.200 * 726

Enthalpy = -145.2kJ

It would take -145.2kJ for 0.200 mol of methanol to undego the combustion reaction.

8 0
3 years ago
How many protons are in nitrogen-15?
valentina_108 [34]
7 protons. As well as in nitrogen-14. The difference between nitrogen-14 and nitrogen-15 is in a number of neutrons. In nitrogen-14 - 7 neutrons, in nitrogen-15 - 8 neutrons. 
4 0
3 years ago
The analogy that forms the basis of the octet rule compares covalent valence
o-na [289]

Answer:

b

Explanation:

orbital overlap electron densities.

3 0
3 years ago
Read 2 more answers
How many grams are in 4.5 x 10^22 molecules of water
Luden [163]

Answer:

1.35 g

Explanation:

water is h2o, so the molar mass is 1.01x2+16.00=18.02. divide 4.5 x 10^22 by 6.022 x 10^23 to get 7.5 x 10^-2 (2 sig figs). 18.02 x 7.5 x 10^-2 is 1.35 g

8 0
3 years ago
C2h4 3 o2 2 co2 2 h2o
Marat540 [252]
Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole=  32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2    /  1mol of CO2
___________  / _____________ = Cancel the queal ( O2)
                       / 32.00c O2
                      /
                     /
Multiply the top and divide by the bottom 
0.624 mol CO x 1mol CO2 = 0.624 divide by 32.00 O2 =0.0195
You should look at the giving number ( how many num u gor ever there) 
Ur answer should have the same # as ur givin so 
= 0.0195 
= .0195 mol of CO2
3 0
3 years ago
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