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Alekssandra [29.7K]
4 years ago
11

Why does inhaled air need to be warmed filtered and moistened?

Chemistry
1 answer:
bearhunter [10]4 years ago
4 0
<span>     The body has to do this to make sure and or to prevent damage to the delicate tissues that form the Respiratory System. This is important because </span>Your body's organs, such as your heart and brain, need oxygen-rich blood to work well. (if it gets damaged by the Cold/Dry air you breath in on a daily)<span><span>Respiratory failure </span>also can occur if your lungs can't properly remove carbon dioxide (a waste gas) from your blood. Too much carbon dioxide in your blood can harm your body's organs.

Hopefully i helped ^.^ please mark brainly if its a possibility~
</span>


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Help please ill give a free thanks WHATEVER just help Bryan is doing a triathlon and you need to calculate his average speed for
serg [7]

Answer:

thermal conductor

Explanation:

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3 years ago
The Reaction
Effectus [21]

Answer:

Explanation:

From the information given:

We can say that the rate of reaction is utilized to decide the reaction speed, and it is subject to the rate constant.

The power of concentration related to the rate equation can be said to be the order of the reaction.

For zero-order reaction: it is the reaction whose rate is free and not dependent on the reactant's concentration.  

Concentration-time reaction is given as;

\mathbf{[A] = [A_o] -kt ---- (1)}

where;

t = time

k = rate constant

A_o = initial concentration of reactant

Thus, the plot between [A] and t needs to be a straight line.

On the other hand, The First order reaction is the reaction whose rate is straightforwardly corresponding to the reactant's concentration.  

Its concentration-time relation can be expressed as,

\mathbf{In([A])= In ([A_o])-kt   ---- (2)}

t = time

k = rate constant

[A_o] = initial concentration of the reactant

Then, the plot between [A] & t requires to be a straight line.

Presently, the plot between ln([A]) vs time appears to be in a straight line with the slope of the line equivalents to the rate constant (k).

hence,

slope = -k

Then;

\mathbf{k = -slope  ---- (3)}

Now; to discover the activation energy we need to utilize Arrhenius relation which is given as,

\mathbf{In(k) = In(K_o) - \dfrac{E_o}{RT}  ---- (4)}

From the above equation;

k_o = arrhenius parameter

Ea = activation energy

R = 8.314 J/mol.K

T = temperature in Kelvin

From the data given  for concentration vs time;

t[min]      Ca(mol/L)

0                      2

5                     1.6

9                     1.35

15                   1.1

22                    0.87

30                    0.7

40                    0.53

60                    0.35

a)

Since we can deduce the order of the reaction,

Let's assume that it is a zero-order reaction, Thus, the plot of Ca vs t can be seen in the first image attached below;

From the diagram, it is clear and obvious that it is NOT a straight line.

Thus, we conclude that this order is NOT a zero-order.

However, let also assume that order is first order,

Now, from the second diagram showing the plot of ln(Ca) vs t, we can deduce that it is a straight line which implies that it is the order of the reaction is first order.

Therefore, the equation for the first order is given as;

\mathbf{In([A]) = In ([A_o])- kt}

Recall that: the slope of the ln(A) v/s time will result in a rate constant,

Thus, from the graph we have;

slope = -0.0289 mol/L.min and:

slope = - k

Hence;

rate constant = k = 0.0289 mol/L.min and the order = 1st order

b)

On the off chance that we need to take more data points, we will like to take the data point in the scope of 40 min to 60 min time interval, on the grounds that the significant deviation is seen there. more information focuses will imply more accuracy.

8 0
3 years ago
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OlgaM077 [116]

Answer:

a chemical reaction

Explanation:

The fact that you are combining two different elements together makes this a chemical reaction. (hope that helps)

3 0
3 years ago
At what stage in c.elegans does cell differentiation occur?<br> zygote<br> larva<br> egg<br> adult
Mila [183]
I'm pretty sure it's larva hope this helps
4 0
3 years ago
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I dont want to write, so you know what the last option is

Explanation:

:) hope this helps

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