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Bad White [126]
2 years ago
13

The length r of a rope should be at least 5 inches how would you write that as an inequality​

Mathematics
1 answer:
sp2606 [1]2 years ago
6 0

Answer:

r is greater than or equal to 5 inches

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Find the unknown side length x. ​
Ganezh [65]

Answer:

x = \sqrt{65}

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

4^{2} + 7^{2} = x^{2}

16 + 49 = x^{2}

65 = x^{2}

x = sq rt 65

6 0
2 years ago
A pipe s leaking at 1.5 cups per day how many gallons per week is the pipe leaking
kkurt [141]
1.77 so i wish u good lock
8 0
3 years ago
PQRS is an isosceles trapezoid and m
Otrada [13]

Answer:

i have no idea what it is so good luck

Step-by-step explanation:

3 0
3 years ago
12 x 1) +(6x1000) it has to be decimal form
Firdavs [7]

Answer:

I got 6.012 times 10^3

Step-by-step explanation:

I'm not sure how to make it into decimal form but maybe that number can help you. Hopefully it's correct

6 0
2 years ago
determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.17, 14, 11, 8,
MArishka [77]

The common difference of the sequence is -3 and the fifth term is 5

<h3>How to determine the common difference?</h3>

The sequence is given as:

17, 14, 11, 8....

The common difference is

d = T2 - T1

So, we have

d = 14 - 17

Evaluate

d = -3

Hence, the common difference of the sequence is -3

<h3>How to determine the fifth term?</h3>

The fifth term is calculated as:

T5 = a + 4d

Where

a = T1 = 17

d = -3

So, we have:

T5 = 17 - 4 * 3

Evaluate

T5 = 5

Hence, the fifth term is 5

<h3>How to determine the nth term?</h3>

The nth term is calculated as:

Tn = a + (n - 1)d

Hence, the nth term is Tn = a + (n - 1)d

Read more about arithmetic sequence at:

brainly.com/question/6561461

#SPJ1

6 0
1 year ago
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