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Anvisha [2.4K]
3 years ago
7

Generally the ionization potential in a period increases, but there are some exceptions. The one which is not an exception is

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception

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Properties of metalloids tend to fall in between the properties of metals and nonmetal.
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3 years ago
Salt is the product formed by a reaction in which _______ atoms of an acid are replaced by the atoms of a metal.
UkoKoshka [18]
<span>Salt is the product formed by a reaction in which the hydrogen atoms of an acid are replaced by the atoms of a metal. The salt is formed as a result of the neutralization of the acid by base, that is the metal or positive ion replace the hydrogen ion in the acid. For instance: NaO + H2SO4 = NaSO4 + H2O. In this example, Na [sodium] has replaced the hydrogen in H2SO4, thereby forming the salt NaSO4.</span>
7 0
3 years ago
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In a water molecule (H2O), the oxygen atom has two unshared pairs of electrons and two bonding pairs of electrons. How do the un
vladimir1956 [14]

Answer:

They reduce the bond angle to be slightly lower than the tetrahedral bond angle, approximately 104.45 degrees.

Explanation:

The unshared pair of electrons or lone pair electrons in order to have the minimum repulsion possible with each other pushes the other bonding pairs closer together making the bond angle smaller or bent.

The bond angle is slightly lower than the tetrahedral bond angle of 108 degrees, leaving the water molecule with a bent molecular geometry.

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3 years ago
Why is potasium oxide not used to investigate property of hydrogen gas​
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3 0
3 years ago
PLEASE HELP ME<br><br> what would be the mass of 9.03 x 1021 molecules of hydrobromic acid (HBr)?
Nikitich [7]

We know 1 mole of any atom or molecules contains 6.033 \times 10^{23} atom or molecules.

1 mole of HBr i.e 81 gm/mol contains  6.033 \times 10^{23} atom or molecules.

So, mass of 9.03\times 10^{21} molecules is :

m=\dfrac{81\times 9.03\times 10^{21} }{6.033 \times 10^{23}}\\\\m= 1.21\ gm

Therefore, mass of  9.03\times 10^{21} molecules is 1.21 gm .

Hence, this is the required solution.

7 0
3 years ago
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