Set up a free body diagram.
<span>and by reason, Tcd = Tbd </span>
<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>
<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>
<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
Answer:<em> tried my best to answer your ?s:</em>
<em>B</em>
<em>A</em>
<em>B</em>
<em>D</em>
<em>A</em>
<em>A</em>
<em>B?</em>
<em>Hope this helps!!</em>
Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.
Ella has both dimes (d) and nickels (n) in her piggy bank. She has a total of 36 coins in all, and has 4 more dimes than nickels. Find how much money she has in her piggy bank using a two-variable, two-equation system.
Answer:
C 350W
Explanation:
Given power output to walk on a flat ground to be 300W, h = 0.05x, v = 1.4m/s
m = 70kg and g =9.8m/s².
x = horizontal distance covered
Total energy used = potential energy used in climbing and the energy used in a walking the horizontal distance.
E = mgh + 300t
Where t is the time taken to cover the distance
x = vt and h = 0.05vt
So
E = mg×0.05×vt + 300t
Substituting respective values
E = 70×9.8×0.05×1.4t +300t = 348t
P = E/t = 348W ≈ 350W.
