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3 years ago

would the pressure exerted by the gas in the tank would increase if the scuba tank were to increase in temperature?

Chemistry

1 answer:

ludmilkaskok [199]3 years ago

6 0

Answer:

In fact, a full scuba tank will gain about 5-6 psi for every degree of temperature increase. This is one reason that full tanks should not be left in a hot trunk of a car. A tank filled to 3000 psi could easily reach 3500 psi if the temperature of it increased substantially.

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Which quantities can be measured

chubhunter [2.5K]

Explanation:

Any quantity which can be measured is called a physical quantity.

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3 years ago

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The energy level necessary to enable a reaction to a cure is called the activation true or false

matrenka [14]

The correct answer is true. It was introduced by Svante Arrhenius that activation energy is minimum amount of energy needed to be supplied or released for a chemical reaction to proceed. It is the energy needed to overcome for a reaction to occur.

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4 years ago

The rate constant for a particular zero-order reaction is 0.075 M s-1. If the initial concentration of reactant is 0.537 M it ta

Phoenix [80]

Answer : It takes time for the concentration to decrease to 0.100 M is, 22.4 s

Explanation :

Formula used to calculate the rate constant for zero order reaction.

The expression used is:

$\ln [A]=-kt+\ln [A_o]$

where,

$[A_o]$ = initial concentration = 0.537 M

$[A]$ = final concentration = 0.100 M

t = time = ?

k = rate constant = 0.075 M/s

Now put all the given values in the above expression, we get:

$\ln (0.100)=-0.075\times t+\ln (0.537)$

$t=22.4s$

Therefore, it takes time for the concentration to decrease to 0.100 M is, 22.4 s

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3 years ago

4. To how much water should 50 mL of 12 M hydrochloric acid be added to

Novosadov [1.4K]

Answer : The volume of water added are, 15 mL

Explanation :

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of HCl.

$M_2\text{ and }V_2$ are the final molarity and volume of water.

We are given:

$M_1=12M\\V_1=50mL\\M_2=40M\\V_2=?$

Putting values in above equation, we get:

$12M\times 50mL=40M\times V_2\\\\V_2=15mL$

Hence, the volume of water added are, 15 mL

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3 years ago

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