1.70 × 10³ seconds
<h3>Explanation </h3>
+ 2 e⁻ → 
It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.
Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains 
of Co atoms. It would take 
of electrons to reduce cobalt (II) ions and produce the 
of cobalt atoms.
Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of 
. A current of 0.961 A delivers 0.961 C of charge in one single second. It will take 
to transfer all these charge and deposit 0.500 g of Co.
<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
Answer:
the chemical equation is balanced ❤
