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lyudmila [28]
3 years ago
13

How many grams of AgNO3 are needed to prepare a 75.00 mL solution that is 6.5% (m/v)?

Chemistry
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

Volume of AgNO₃ = 4.9 ml (Approx)

Explanation:

Given:

Total solution = 75 ml

Volume of AgNO₃ = 6.5%

Find:

Volume of AgNO₃

Computation:

Volume of AgNO₃ = Total solution x Volume of AgNO₃

Volume of AgNO₃ = 75 x 6.5%

Volume of AgNO₃ = 4.875

Volume of AgNO₃ = 4.9 ml (Approx)

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