How many grams of AgNO3 are needed to prepare a 75.00 mL solution that is 6.5% (m/v)?
1 answer:
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Answer : The correct option is, (B) 6 mole
Explanation :
Given moles of = 6 moles
Given moles of = 6 moles
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the given balanced reaction, we conclude that
As, 1 moles of react with 2 moles of
So, 6 moles of react with
moles of
From this we conclude that, is an excess reagent and
is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.
Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH
The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles
Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles
Answer:
The structure is given in attached file.
Explanation:
Explanation
2-bromocyclopentamine (Figure attached) is a synthetic compound which is synthesized by substitution reaction of cyclopentamine and hydrobromide. Its molecular formula and molecular mass are C5H10NBr and 164.05 mol/g respectively. It is a very reactive compound so it doesn’t available in pure form, it is present in market as a mixture of 2-bromocyclopentamine and Hydrobromide.
Properties :
Its boiling point is 115 0C
Its melting point is – 75 oC
It is highly flammable
It is highly toxic
It is irritant
It is corrosive in nature
