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1 year ago

Describe how amino acids are categorized by their chemical properties

1 answer:

5 0

Amino acids are categorized by their chemical properties on the basis of the sequence of side chain (R group).

<h3>What are amino acids?</h3>

Amino acids are known as the 'building blocks of the life' as they help in the formation of proteins inside the body.

Side chain of amino acids is specific in nature and are known by the name of R group, these R groups are attached with the alpha carbon atom. R groups characterizes below properties of the molecule:

Shape
Size
Charge and
Reactivity

Hence R group describes the chemical properties of amino acids.

To know more about amino acids, visit the below link:

brainly.com/question/1302816

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A car is traveling at 50mph. How long will it take the car to travel 300 miles?

scoundrel [369]

Answer:

6 hours

Explanation:

If it is traveling at 50mph and needs to reah 300 miles, to figure this problem out you would want to divide 300 by 50 to get 6 hours. So it will take six hours until the car travels 300 miles

Hope this helps.

3 0

2 years ago

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Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 3.50 moles of magnesium

Firdavs [7]

Answer:

$n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO$

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

$n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO$

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3 0

2 years ago

How many more oxygen atoms are in Na2HPO4H(disodium phosphate) then in 2H3PO(Phosphoric Acid)?

Serggg [28]

Answer:

in disodium phosphate = 4 oxygen atoms

in phosphoric acid = 1 oxygen atom

3 0

2 years ago

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Based on the equations below, which metal is the least active? Pb(NO3)2(aq) + Ni (s) --> Ni(NO3)2 (aq)+ Pb(s) Pb(NO3)2(aq) +

viva [34]

Answer:

Explanation:

An active metal is a highly reactive metal. Active metals are found high up in the activity series.

Active metals react with other metals that are lower than them in the activity thereby displacing the lower metals from a solution of their salts. This is what may have happened in the other two reactions.

Ni is the most active metal listed in the question since it can react a compounds with Pb(NO3)2(aq) to liberate Pb metal.

6 0

2 years ago

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

8 0

2 years ago

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