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choli [55]
1 year ago
7

Describe how amino acids are categorized by their chemical properties

Chemistry
1 answer:
Korolek [52]1 year ago
5 0

Amino acids are categorized by their chemical properties on the basis of the sequence of side chain (R group).

<h3>What are amino acids?</h3>

Amino acids are known as the 'building blocks of the life' as they help in the formation of proteins inside the body.

Side chain of amino acids is specific in nature and are known by the name of R group, these R groups are attached with the alpha carbon atom. R groups characterizes below properties of the molecule:

  • Shape
  • Size
  • Charge and
  • Reactivity

Hence R group describes the chemical properties of amino acids.

To know more about amino acids, visit the below link:

brainly.com/question/1302816

#SPJ1

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Explain how you would convert the moles of a compound to the made (grams) of the same compound<br>​
Oduvanchick [21]

Answer:

see notes below

Explanation:

The mole is the mass of substance containing 1 Avogadro's Number of particles. That is, 1 mole substance = 1 formula weight. For elements, 1 mole weight is equal to the atomic weight expressed as grams. For molecules, 1 mole weight is equal to the molecular weight expressed as grams.

1 mole = 1 formula weight

<u>Moles to Grams and Grams to Moles</u>

Grams => Moles

Given grams, moles = mass given / formula weight

*Ask the question => How many formula weights are there in the given mass? => Results is always moles.

Moles => Grams

Given moles,  grams = moles given X formula weight

*Summary

Grams to Moles => divide by formula weight

Moles to Grams => multiply by formula weight

3 0
3 years ago
Maria is baking cookies. She mixes water, flour, sugar, baking powder, butter and chocolate chips and then measures the mass of
Mrrafil [7]

Answer:

The law of conservation of mass was obeyed since some of the mass evaporated while the cookies were baking.

Explanation:

Maria mixes water, flour, sugar, baking powder, butter and chocolate chips and then measures the mass of her ingredients.

Initial mass of ingredients = 1053 g

Final mass = 845 g

All these information are not of any great help.

Law of conservation of mass states that:

For any system closed to all transfers of matter and energy, the mass of the system can not change with respect to time, as system's mass cannot change, any mass can neither be added nor be removed.

In this process of baking, considering the cookies as our system, they never formed a closed system. Hence were free for evaporation.

During the process of baking, water from dough must have evaporated and mass must have reduced.

Hence, the law of conservation of mass was not obeyed.

8 0
3 years ago
Read 2 more answers
What is one property that water and oil do not share
choli [55]

Answer:

Molecules of oil are bigger than of water and therefore do not mix.

Hope this helps

3 0
3 years ago
how much current would be measured in a circuit if the light bulb has a resistance of 6 ohms and a voltage of 36 volts
Stels [109]

Answer:

The right response is "6 A". A further explanation is given below.

Explanation:

The given values are:

Resistance,

R = 6 ohms

Voltage,

V = 36 volts

As we know,

⇒  V=IR

then,

⇒  I=\frac{V}{R}

On substituting the values, we get

⇒     =\frac{36}{6}

⇒     =6 \ A

8 0
2 years ago
Paradichlorobenzene, C6H4Cl2, is a component of mothballs. A solution of 2.00 g in 22.5 g of cyclohexane boils at 82.39 ∘C. The
Rina8888 [55]

Answer:

2.79 °C/m

Explanation:

When a nonvolatile solute is dissolved in a pure solvent, the boiling point of the solvent increases. This property is called ebullioscopy. The temperature change (ΔT) can be calculated by:

ΔT = Kb*W*i

Where Kb is the ebullioscopy constant for the solvent, W is the molality and i is the van't Hoff factor.

W = m1/(M1*m2)

Where m1 is the mass of the solute (in g), M1 is the molar mass of the solute, and m2 is the mass of the solvent (in kg).

The van't Hoff factor represents the dissociation of the elements. For an organic molecule, we can approximate i = 1. Thus:

m1 = 2.00 g

M1 = 147 g/mol

m2 = 0.0225 kg

W = 2/(147*0.0225)

W = 0.6047 mol/kg

(82.39 - 80.70) = Kb*0.6047*1

0.6047Kb = 1.69

Kb = 2.79 °C/m

4 0
3 years ago
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