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Ilya [14]
3 years ago
5

The equation shows neutralization of an acid and a base to produce a salt and water

Chemistry
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

tRUE??

Explanation:

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What is the reduction half-reaction for the following unbalanced redox equation?
bazaltina [42]
First find the oxidation states of the various atoms: 
<span>in Cr2O2 2- Cr @ +1; In NH3 N @ +3; in CrO3 Cr @ +3, N2 N @ 0 </span>
<span>Note that N gained electrons, ie, was reduced; Cr was oxidized </span>
<span>Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out </span>
<span>B.NH4+ → N2 </span>

<span>Which of the following is an oxidation half-reaction? </span>
<span>A.Sn 2+ →Sn 4+ + 2e- </span>
<span>Sn lost electrons so it got oxidized</span>
5 0
3 years ago
Read 2 more answers
Question 11. Identify the reducing agent <br> Sn+2 + AG 0 —&gt; Sn0 + Ag+
Temka [501]

Answer:

Ag 0 is the reducing agent.

Explanation:

Reducing -> gaining electrons

Oxidizing -> losing electrons

Ag lost electrons (became more positive) since it went from a 0 charge to a +1 charge. Therefore it was oxidized. Ag+ is the oxidized product. Reactants that create an oxidized product are called reducing agents. This would make Ag 0 the reducing agent in this reaction.

4 0
2 years ago
Cosity a letter to our mother
kotykmax [81]

An answer befitting your question…

Hi mom, I’m having troubles with my teachers. They are cruel to me and I cannot concentrate. I think if we changed schools it would be much better. Thank you mom.
6 0
2 years ago
Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.
BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
  • Reading the Periodic Table
  • Writing Compounds
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

<u>Step 3: Use Dimensional Analysis</u>

<u />6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} ) = 511.901 g NO₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

511.901 g NO₂ ≈ 510 g NO₂

6 0
2 years ago
What statement is incorrect about this oxidation-reduction reaction? 2 SO2(g) + O2(g) → 2 SO3(g) What statement is incorrect abo
Leno4ka [110]

Answer:

The incorrect statement is: SO₂ gains electrons                      

Explanation:

A chemical reaction that involves the simultaneous transfer of electrons between two chemical species, is known as the redox reaction.

Given chemical reaction: 2SO₂(g) + O₂(g) → 2SO₃(g)

In this redox reaction, S is present in +4 oxidation state in SO₂ and +6 oxidation state SO₃. Whereas, O is present in 0 oxidation state in O₂ and -2 oxidation state in SO₃.

<u>Therefore, SO₂ loses electrons and thus gets oxidized. Whereas, O₂ gains electrons and thus gets reduced. </u>

<u>In this reaction, SO₂ is the reducing agent and O₂ is the oxidizing agent.</u>

6 0
3 years ago
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