P x V = n x R x T
P x 73 = 2.97 x 0.082 x 298
P x 73 = 72.57492
P = 72.57492 / 73
P = 1.0 atm
hope this helps!
Answer:
C
Explanation:
Their are pressure sensers in the water that will detect high pressure and set of scales that are currently detecting semic waves and trigger sierns.
Answer:
FADH₂ → Q coenzyme → Complex III → c cytochrome → Complex IV → O₂
Explanation:
During oxidative phosphorylation, the electrons from NADH and FADH₂ are combined with O₂ and the energy released in the process is used to synthesize ATP from ADP.
The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.
Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the <em>b</em> cytochrome to the <em>c</em> cytochrome. This <em>c </em>cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.
Atomic number is equal to protons and electrons, so the answer is 5
Answer : The half life of 28-Mg in hours is, 6.94
Explanation :
First we have to calculate the rate constant.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = time passed by the sample = 48.0 hr
a = initial amount of the reactant disintegrate = 53500
a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520
Now put all the given values in above equation, we get
Now we have to calculate the half-life.
Therefore, the half life of 28-Mg in hours is, 6.94
