2 years ago

The diagram pictured shows a loop of wire being rotated at a constant rate about an axis in a uniform magnetic field.

1 answer:

7 0

The rotation is probably n

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joja [24]

Answer:

Aerobic exercise became part of this movement in the 1970s.

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3 years ago

ddd [48]

B is the right answer. Multiply numbers you get the answer

3 0

2 years ago

Dovator [93]

Answer:

AFter 3.5 s, the wagon is moving at: $4.62\,\,\frac{m}{s}$

Explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

$F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}$

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

$v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}$

7 0

3 years ago

vladimir1956 [14]

Answer:

acceleration= velocity ÷ time

Explanation:

the question is outrageous

4 0

2 years ago

BlackZzzverrR [31]

C would be the answer

4 0

2 years ago