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Rzqust [24]
3 years ago
7

Why does our sun appear larger than any other star in our galaxy

Physics
2 answers:
MArishka [77]3 years ago
5 0

Answer:

It is the closest star to us. other bigger stars may seem small, but that is because they are far away. The more closer an object is, the smaller it seems to be.

Explanation:

Hope this helps!

Doss [256]3 years ago
3 0

Answer:

The closer and bigger the star, the larger the star appears.

Explanation:

Since the sun is closer to us it shows up way larger than other stars in our galaxy.

Have a great day.

You might be interested in
Two 5.0 kilogram objects have different gravitational potential energies. What property of the objects must differ?
ipn [44]

Answer:

Height.

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Hence, the property of the object (having a mass of 5 kilograms) which must differ to have different gravitational potential energies is the height from which they are falling from.

The object having the higher height would have a greater gravitational potential energy than the lower object.

7 0
2 years ago
In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 2.8 m/s. However, this speed is inade
erastova [34]

Answer:

3.95979 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow as=\frac{v^2-u^2}{2}\\\Rightarrow as=\frac{0^2-2.8^2}{2}\\\Rightarrow as=-3.92

Here s=\frac{1}{2}s

\\\Rightarrow as=-7.84\ m/s^2

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -7.84}\\\Rightarrow u=3.95979\ m/s

Initial velocity of the puck should be 3.95979 m/s

8 0
2 years ago
A swimming pool has the shape of a box with a base that measures 30 m by 12 m and a uniform depth of 2.2 m. How much work is req
Alex777 [14]

Answer:

853776 J

Explanation:

The work-energy needs to pump water out of the pool is the product of the weight of water and distance h

E = Wh = mgh

Since water mass is a body of water we can treat it as the product of density 1000kg/m3 and volume, which is the product of base area and uniform height h

m = \rho V = \rho \int\limits^{2.2}_0 {A} \, dh

Therefore:

E = mgh = g\rho A\int\limits^{2.2}_0 {h} \, dh\\E = 9.8*1000*30*12[h^2/2]^{2.2}_0 = 1764000(2.2^2 - 0^2) = 853776 J

5 0
2 years ago
You're conducting a physics experiment on another planet. You drop a rock from a height of 2.1 m and it hits the ground 0.6 seco
umka21 [38]

The formula to use is the one that connects the acceleration,
the distance fallen, and the time spent falling:

         Distance = 1/2 a T² .

You said  2.1 meters in 0.6 second .

                                                         2.1 m              = 1/2 a  (0.6 sec)²

Multiply each side by  2 :                  4.2 m              =       a (0.6 sec)²

Divide each side by (0.6 sec)² =     (4.2/0.36) m/s² =        a

                                                         a = (11 and 2/3) m/s²

                                        (about 19% more than Earth's gravity)

3 0
3 years ago
Read 2 more answers
HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW
Andrej [43]

Answer:

c

Explanation:

................................................

7 0
2 years ago
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