All categories

3 years ago

What number and type of hybrid orbital(s) form(s) when one p and one s atomic orbital mix?

1 answer:

3 0

Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

<h3>What are orbitals?</h3>

Orbital is the place around nucleus where mostly the electrons are present. There are four types of orbitals are present, s, p, d, and f.

The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.

Thus, two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

Learn more about orbitals

brainly.com/question/18914648

#SPJ4

You might be interested in

A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1

zubka84 [21]

Explanation:

(1). Formula to calculate the potential difference is as follows.

$\Delta V = -\int E dr$

= $-\int \frac{kq}{r^{2}} dr$

= $\frac{kq}{r_{f}} - \frac{kq}{r_{i}}$

= $\frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}$

= $\frac{9 \times 10^{9} \times 3.30 \times 10^{-9}(0.1 - 0.015)}{0.1 \times 0.015}$

= 38.7 volts

Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2). Now, formula to calculate the energy stored in the capacitor is as follows.

E = $\frac{1}{2}QV$

= $\frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V$

= $6.39 \times 10^{-8} J$

Thus, the electric-field energy stored in the capacitor is $6.39 \times 10^{-8} J$ .

7 0

3 years ago

Read 2 more answers

A piston-cylinder device initially contains 1.4 kg saturated liquid water at 200oC. Now heat is transferred to the water until t

postnew [5]

Answer:

Explanation:

Given

mass of saturated liquid water $m=1.4\ kg$

at $200^{\circ}$ specific volume is $\nu =0.001157\ m^3\kg$ (From Table A-4,Saturated water Temperature table)

$V_1=m\nu _1$

$V_1=1.4\times 0.001157$

$V_1=1.6198\times 10^{-3}\ m^3$

Final Volume $V_2=4V_1$

$V_2=4\times (1.6198\times 10^{-3})$

$V_2=6.4792\times 10^{-3}\ m^3$

Specific volume at this stage

$\nu _2=\frac{V_2}{m}$

$\nu _2=\frac{6.4792\times 10^{-3}}{1.4}$

$\nu _2=0.004628\ m^3/kg$

Now we see the value and find the temperature it corresponds to specific volume at vapor stage in the table.

$T_2=T_1^{*}+\frac{T_2^{*}-T_1^{*}}{\alpha _2^{*}-\alpha _1^{*}}\times (\alpha _2-\alpha _1^{*})$

$T_2=370^{\circ}+\frac{373.95-370}{0.003106-0.004953}\times (0.004628-0.004953)$

$T_2=370.7^{\circ} C$

4 0

3 years ago

What is currently the most supported theory about the future of the universe

mamaluj [8]

the answer is B! it would continue to expand.....just took the test XD

8 0

3 years ago

Read 2 more answers

Bài 4: Một vật dao động điều hòa với phương trình x = 4cos(4πt - π/3) cm.

ra1l [238]

Answer:

Explanation:

6 0

3 years ago

. A bathysphere used for deep-sea exploration has a radius of 1.50 m and a mass of 1.20 104 kg. To dive, this submarine takes on

dangina [55]

Answer:

Explanation:

Given that,

Bathysphere radius

r = 1.5m

Mass of bathysphere

M = 1.2 × 10⁴ kg

Constant speed of descending.

v = 1.2m/s

Resistive force

Fr = 1100N upward direction

Density of water

ρ = 1.03 × 10³kg/m³

The volume of the bathysphere can be calculated using

V = 4πr³ / 3

V = 4π × 1.5³ / 3

V = 14.14 m³

The Bouyant force can be calculated using

Fb = ρgV

Fb = 1.03 × 10³ × 9.81 × 14.14

Fb = 142,846.18 N

Buoyant force is acting upward

Weight of the bathysphere

W = mg

W = 1.2 × 10⁴ × 9.81

W = 117,720 N

Weight is acting downward

The net positive buoyant using resolving

Fb+ = Fb — W

Fb+ = 142,846.18 — 117,720

Fb+ = 25,126.18 N

The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force

W = Fb+ + Fr

W = 25,126.18 + 1100

W = 26,226.18

mg = 26,226.18

m = 26,226.18 / 9.81

m = 2673.4kg

Mass of submarine is 2673.4kg

8 0

3 years ago