All categories

3 years ago

ZnSO4 + + LINO, → ---- Zn(NO3)2 + Li,SO4 Balanced equation

Chemistry

1 answer:

Tanzania [10]3 years ago

4 0

Answer:

ZnSO4 + 2LiNO3 → Zn(NO3)2 + Li2SO4

Explanation:

There's many resources on web that can assist you with this concept:

https://en.intl.chemicalaid.com/tools/equationbalancer.php

https://www.webqc.org/balance.php

You might be interested in

Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. when 2.59 g of magnesium ribbon bu

stepan [7]

Burning Mg in the air and reacting with O2 forming a white powder of MnO

So the equation is going to be:
Mn + O2 ⇒ MnO (this equation is not conserved)

to make it equilibrium:
1- First we should put 2Mno to equal the O2 on both sides.
So it will be:
Mg + O2⇒ 2MgO
2- Second we should put 2Mn to equal the Mn on both sides.
2Mg + O2⇒ 2MgO (this equation is conserved)
After putting the physical states the final equilibrium equation is going to be:
Δ
2Mg(s) + O2(g)⇒ 2MgO(s)

4 0

4 years ago

If a sample contains 70.0 % of the R enantiomer and 30.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?

NeTakaya

Answer:

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

$= |\frac{R - S}{R + S} |\times 100\\\\= |\frac{70 - 30}{70 + 30}| \times 100\\\\= 40\%$

Hence, the enantiomeric excess of the mixture is 40%

3 0

3 years ago

Harriet has an itch in her throat, and she begins to cough. she reaches for a cup of water to drink. which action is carried out

Nikitich [7]

when she reaches for the cup that is somatic nervous system. when she begins to cough

8 0

3 years ago

What is the collection of protons and neutrons in the center of an atom called

sdas [7]

If I am correct it should be nucleons

8 0

3 years ago

Read 2 more answers

an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m

bogdanovich [222]

Answer:

$P_2=1.1x10^6Pa$

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

$P_1V_1=P_2V_2$

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

$P_2=\frac{P_1V_1}{V_2}$

Consider that the given initial pressure is also equal to Pa:

$P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa$

Which stands for a pressure increase when volume decreases.

Regards.

4 0

3 years ago