Hyy mate......
Here is your answer ......
<h2>
➡️⏺️Oxygen⏺️⬅️</h2>
1️⃣Name: Oxygen
2️⃣State : non-metal
3️⃣Family:Oxide
4️⃣Protons: 8
Electron:8
Neutron: 8
<u>Hope it will help you</u><u>.</u><u>.</u><u>.</u>
<u>Thanks for asking....</u>
The solution would be like
this for this specific problem:
<span><span>
E</span>=</span><span>mc</span>ΔT<span> <span>
= (</span>15<span> g</span><span>)(</span>1.91<span> <span>J<span><span>g∘</span>C</span></span>)(</span>25<span><span> ∘</span>C</span>−15<span><span> ∘</span>C</span><span>)
</span></span>= 28.65 * 10
= 286.5
<span>
I hope this helps and if you have any further questions, please don’t hesitate
to ask again. </span>
Answer:
Hexanol has the highest boiling point.
Explanation:
Boiling points of all give compounds are as follow,
Hexanol = 157 °C
Hexanal = 129 °C
Hexanone = 128 °C
Hexane = 68 °C
Types of Interactions found in these compounds are,
Hexanol = Hydrogen Bonding & London Dispersion Forces
Hexanal = Dipole-Dipole Interactions & London Dispersion Forces
Hexanone = Dipole-Dipole Interactions & London Dispersion Forces
Hexane = Only London Dispersion Forces
Strength of Intermolecular Forces:
Hydrogen forces are stronger than Dipole-Dipole Interactions, and Dipole-Dipole Interactions are stronger than London Dispersion Forces.
Result:
Hence, due to presence of strong Hydrogen Bond Interactions Hexanol has the highest Boiling Point.
Answer:
6.67 moles of NH₃
Explanation:
From the equation of reaction,
4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(g),
4 moles of NH₃ will produce 6 moles of 6H₂O,
X moles of NH₃ will produce 10 moles of H₂O
X = (10 * 4) / 6
X = 6.67 moles of NH₃
6.67 moles of NH₃ will produce 10 moles of H₂O
Answer : The molarity of the solution is, 1.1 M LiCl
Explanation : Given,
Mass of 
= 32 g
Volume of solution = 655 mL
Molar mass of = 42.4 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of the solution is, 1.1 M LiCl
