Answer:
0.877 mol
Step-by-step explanation:
We can use the<em> Ideal Gas Law </em>to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 646 torr
V = 25.0 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 22.0 °C
Calculations:
(a) <em>Convert the pressure to atmospheres
</em>
p = 646 torr × (1 atm/760 torr) = 0.8500 atm
(b) <em>Convert the temperature to kelvins
</em>
T = (22.0 + 273.15) K = 295.15 K
(c) <em>Calculate the number of moles
</em>
n = (0.8500 × 25.0)/(0.082 06 × 295.15)
= 0.877 mol
Answer:

Explanation:
Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.
- The change in temperature is the difference between the initial temperature to the final temperature.
- The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
- ΔT= final temperature - initial temperature
- ΔT= 67°C - 23°C
- ΔT= 44°C
Now we know all the values.
- m= 26.3 g
- c= 0.930 J/g °C
- ΔT= 44°C
Substitute the values into the formula.

Multiply the first two numbers together. The units of grams cancel.

Multiply again. This time, the units of degrees Celsius cancel.

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.
Answer:
t ≈ 235.47 secs
Explanation:
<u>Calculate how long it will take the transformation to go to 88% completion</u>
Given that Avrami equation ( <em>y </em>)= 1 - exp( - kt^n )
n = 2.3
t = 145 secs
reaction = 50% after t = 145 secs
Reaction = 88% after t = ?
attached below is a detailed solution
Answer:
Explanation:
The neutral one has atomic structure 1s2 2s2
The one with a positive charge could be 1s2 2s which has lost one of its 2s electrons.
Physical change is a change in size, shape, state or solution. You still have the same material.
Chemical change forms a new substance. It can be seen by a color change, odor change, gas formation, precipitate formation or large change in energy.
Hope it helps