Iron (III) oxide= Fe2O3 1) Find the gfm (gram formula mass, the gfm is the grams per mole. So, you’re pretty much finding one mole of Fe2O3) of Fe2O3 2 Fe: 2(55.845) 3 O: 3(15.9994) =160 gfm 2) multiply gfm by mole number 160(1 mole of Fe2O3 is 160. What are 5.6 moles?) 160 x 5.6 = 896g
The enthalpy change is negative.
The other statements are false because:
Can take place without a catalyst
Energy is given out to the surroundings.
Kinetic energy of products is higher.