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bogdanovich [222]
3 years ago
11

Calculate the pressure exerted on an elevator floor which has an area of 6 m2, if 20 people whose combined force is 1500 N are s

tanding on it
Chemistry
1 answer:
Zinaida [17]3 years ago
7 0
Https://brainly.in/question/8068288
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Convert 500.45 g to kg (do not use Scientific Notation)
MakcuM [25]

Answer:

0.50045

Explanation:

Because you have to look at a conversion table and move the decimal three places to the left. Hope this helps!

8 0
3 years ago
How many moles of ammonia are in 735. mL of a 4.25 M aqueous ammonia solution?
zysi [14]

Answer:

*moles = molarity(M=moles/L) * volume (L)

so, you have 4.25 * 0.735 moles

*NH3

* M=n/v

*To determine the number of significant figures in a number use the following 3 rules: Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant.

6 0
3 years ago
How does gravity affect the inner planets? (site 2)<br><br>                 <br><br>​
ikadub [295]

The presence of an atmosphere, temperature, and distance from the Sun do not affect a planet's gravity. Are the objects in the solar system still or are they in motion? The Sun's gravity pulls the planets in orbit around it, and some planets pull moons in orbit around them.

7 0
3 years ago
Read 2 more answers
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 ℃, and the temperature af
gtnhenbr [62]

Answer:fH = - 3,255.7 kJ/mol

Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
3 years ago
Write the equilibrium constant expression for this reaction: CH3OH (aq)+Cl-(aq)-&gt; CH3Cl(aq)+OH-(aq)
bulgar [2K]

Answer: K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.

The given balanced equilibrium reaction is:

 CH_3OH(aq)+Cl^-(aq)\rightleftharpoons CH_3Cl(aq)+OH^-(aq)

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}

Thus the equilibrium constant expression for this reaction is K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}

5 0
3 years ago
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