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hodyreva [135]
3 years ago
14

Consider a thin, spherical shell of radius 14.5 cm with a total charge of 29.5 µC distributed uniformly on its surface. (a) Find

the electric field 10.0 cm from the center of the charge distribution. (b) Find the electric field 21.5 cm from the center of the charge distribution.
Physics
1 answer:
ra1l [238]3 years ago
8 0

Answer:

10.0     zero, by Gauss' Law the symmetrical distribution will produce no internal electric fields

21.5     E = k Q / R^2     behaves as if all charge were at center

E = 9 E9 * 29.5 E-6 / .215^2 = 5.74E6 N/C

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At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro
Feliz [49]

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

8 0
3 years ago
What does conserving mass mean in a chemical equation?
mixas84 [53]

There is equal number of each type of atom on the reactant and product side.

<u>Explanation:</u>

Conserving mass in a chemical reaction means  balancing the conservation of mass through  the law and balancing the atoms. There is equal number of each type of atom on the reactant and product side.

There is an equal amount of atoms on both the sides that is the reactant side as well as the product side, it balances the atoms to have a conservation of mass, through the law of conservation of mass.

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4 0
3 years ago
Convert from scientific notation to standard form<br> 9.512 x 10-8
eduard
Standard form: 0.00000009512
5 0
3 years ago
A skier goes down a slope and detaches from the ground moving in the horizontal direction with a speed of 25m / s. The slope has
zepelin [54]

Answer:

107 m down the incline

Explanation:

Given:

v₀ₓ = 25 m/s

v₀ᵧ = 0 m/s

aₓ = 0 m/s²

aᵧ = -10 m/s²

-Δy/Δx = tan 35°

Find: d

First, find Δy and Δx in terms of t.

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (0 m/s) t + ½ (-10 m/s²) t²

Δy = -5t²

Δx = v₀ₓ t + ½ aₓ t²

Δx = (25 m/s) t + ½ (0 m/s²) t²

Δx = 25t

Substitute:

-(-5t²) / (25t) = tan 35°

t/5 = tan 35°

t = 5 tan 35°

t ≈ 3.50 s

Now find Δy and Δx.

Δy ≈ -61.3 m

Δx ≈ 87.5 m

Therefore, the distance down the incline is:

d = √(x² + y²)

d ≈ 107 m

8 0
4 years ago
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