Ask question

Ask question

All categories

3 years ago

15

Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th

e child pushing the sled is exerting a horizontal a force of 8.00 N. There is a force of friction of 5.00 N.

1 answer:

djverab [1.8K]3 years ago

4 0

Answer:

okay sooo the weight is: 294 n

the normal force is 286 n

the acceleration is: -0.38 m/s²

You might be interested in

Which alkali metal is most reactive<br>

Doss [256]

Francium is the most reactive alkali metal

8 0

2 years ago

g the space in between two glass sheets has a volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed

Keith_Richards [23]

Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of $0.025 \ m^3$ . If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is $V_{rms} = 425.75 \ m/s$

Explanation:

From the question we are told that

The volume of the space in between the two glass sheet is $a = 0.025 \ m^3$

The temperature of the gas is $T = 290 \ K$

The atomic mass of Argon is $m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg$

Generally the root mean square velocity is mathematically represented as

$V_{rms} = \sqrt{\frac{3 K T}{ m } }$

Here K is the Boltzmann constant with value $k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}$

So

$V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }$

=> $V_{rms} = 425.75 \ m/s$

3 0

3 years ago

How did scientists determine the age of our universe?

noname [10]

Answer:

Astronomers estimate the age of the universe in two ways: 1) by looking for the oldest stars; and 2) by measuring the rate of expansion of the universe and extrapolating back to the Big Bang; just as crime detectives can trace the origin of a bullet from the holes in a wall.

Explanation:

4 0

3 years ago

Two long, straight, parallel wires separated by a distance of 20 cm carry currents of 30 A and 40 A in opposite directions. What

solmaris [256]

Answer:

Resultant magnetic field = $3.3\times 10^{-5} T$

Explanation:

We are given that two long straight, parallel wires separated by a distance 20 cm

Le two wires A and B

$r_1=15cm=0.15 m,r_2=25cm=0.25m$

Current flowing in wire= $I_A$ =30 A

Current flowing in wire B= $I_B=$ 40 A

We have to find the magnitude of magnetic field at a point 15 cm from wire A and 25 cm from wire B

Magnetic field due to current $I_A,B_1=\frac{\mu_0}{4\pi}\times\frac{2I_A}{r_1}$

Magnetic field due to current $I_A,B_1=[tex]10^{-7}\times \frac{2\times 30}{0.15}=4\times 10^{-5}$ T

Magnetic field due to current $I_B,B_2=10^{-7}\times \frac{2\times 40}{0.25}=10^{-7}\times 320$ T

Magnetic field due to current $I_B,B_2=3.2\times 10^{-5}$

Angle between $B_1,and\;B_2=\phi=90^{\circ}+\theta$

$sin\theta=\frac{0.15}{0.25}=\frac{3}{5}$

Resultant magnetic field = $\sqrt{B^2_1+B^2_2-2B_1B_2Cos\phi}$

Resultant magnetic field = $\sqrt{(4\times 10^{-5})^2+(3.2\times 10^{-5})^2-2\times 4\times 10^{-5}\times 3.2\times 10^{-5} cos (90^{\circ}+\theta)}$

Resultant magnetic field = $\sqrt{16\times 10^{-10}+10.24\times 10^{-10}-25.6\times 10^{-10}\times \frac{3}{5}}$

Resultant magnetic field = $\sqrt{10.88}\times 10^{-5}$

Resultant magnetic field = $3.3\times 10^{-5} T$

5 0

4 years ago

A water droplet falling in the atmosphere is spherical. Assume that as the droplet passes through a cloud, it acquires mass at a

ArbitrLikvidat [17]

Answer:

it b

Explanation:

bc A water droplet falling in the atmosphere is spherical

4 0

3 years ago