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Tatiana [17]
3 years ago
6

Extra Stoichiometry Practice

Chemistry
1 answer:
Irina-Kira [14]3 years ago
8 0

Answer: 50. 4g

Explanation:

First calculate number of moles of aluminium in 38.8g

Moles = 38.8g/ 26.982mol/g

= 1.44mol

By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.

4 = 2

1.4 = x

Find the value of x

x= (1.4×2)/4= 0.72 mol

0.72 moles of aluminium oxide are produced from 38.8g of aluminium

Now find the mass of aluminium produced.

Mass = moles × molar mass

= 0.72mol × 69.93 mol/g

= 50.4g

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how many grams of CsXeF7 can be produced from the reaction of 15.2 grams of CsF and 260 grams of XeF6?
Sveta_85 [38]

Answer:

39.72 g

Explanation:

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Mass of Cs[XeF₇] = ?

Solution:

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CsF + XeF₆   →  Cs[XeF₇]

Number of moles of CsF:

Number of moles = mass/ molar mass

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Number of moles = 0.1 mol

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Number of moles = mass/ molar mass

Number of moles = 260 g/245.28 g/mol

Number of moles = 1.06 mol

Now we will compare the moles of Cs[XeF₇] with both reactants.

                            CsF               :            Cs[XeF₇]

                               1                 :                 1

                             0.1                :              0.1

                             XeF₆            :           Cs[XeF₇]

                                 1               :               1

                                1.06           ;              1.06

Number of moles of Cs[XeF₇] produce by  CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].

Mass of Cs[XeF₇]:

Mass = number of moles × molar mass

Mass = 0.1 mol × 397.2 g/mol

Mass = 39.72 g

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3 years ago
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