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valkas [14]
3 years ago
13

Why does the globe lean to the left?

Physics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

Earth is on a tilted axis.

Explanation:

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a metal of length 15.04cm is heated until its temperature rises by 65°c. if its new length is 16.00m calculate its linear expans
spin [16.1K]

Answer:

ΔL = L0 C ΔT

We need to find C the constant of expansivity

C = ΔL / (L0 ΔT)

C = .96 / (15.04 * 65) = 9.82 * 10^-4 / deg C

5 0
2 years ago
Two electrons travel towards each other at 0.2 c parallel to the laboratory x-axis. What is the relative velocity of one electro
Leya [2.2K]

1) In the reference frame of one electron: 0.38c

To find the relative velocity of one electron with respect to the other, we must use the following formula:

u'=\frac{u-v}{1-\frac{uv}{c^2}}

where

u is the velocity of one electron

v is the velocity of the second electron

c is the speed of light

In this problem:

u = 0.2c

v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)

Substituting, we find:

u'=\frac{0.2c+0.2c}{1+\frac{(0.2c)(0.2c)}{c^2}}=\frac{0.4c}{1+0.04}=0.38c

2) In the reference frame of the laboratory: -0.2c and +0.2c

In this case, there is no calculation to be done. In fact, we are already given the speed of the two electrons; we are also told that they travel in opposite direction, so their velocities are

+0.2c

-0.2c

5 0
3 years ago
PLEASE HELP! Compare and contrast between reflection and refraction. Be sure to be specific in your explanation and state in you
horsena [70]

Most ultrasound technicians train in an associates degree, but can also get a bachelors degree in the field. There is also certification programs you can go through. Hope this helped!!! :)

7 0
4 years ago
A 3.9 kg ball traveling towards a soccer player at a velocity of -3.5 m/s rebounds off the soccer player's foot at a velocity of
Tresset [83]

Answer: 2.92 s

Explanation:

Given

Mass of ball is m=3.9\ kg

The initial velocity of the ball is u=-3.5\ m/s

Velocity after the rebound is v=15.9\ m/s

Force during the contact is F=25.9\ N

We know, change in momentum is Impulse

\Rightarrow F\cdot \Delta t=m(\Delta v)

\Rightarrow 25.9\cdot \Delta t=3.9(15.9-(-3.5))\\\\\Rightarrow \Delta t=\dfrac{3.9\times 19.4}{25.9}=2.92\ s

Thus, the force is applied for 2.92 s

4 0
3 years ago
Given this measurement 2642 ft, how many significant figures are there?
Stolb23 [73]
4 sig figs. Just count
8 0
3 years ago
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