A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second.
2 answers:
<u>Answer:</u> The horizontal velocity of rover is 1.73 m/s
<u>Explanation:</u>
Horizontal velocity is defined as the velocity of body proceeding in the horizontal direction. This velocity proceeds in the 'x' direction.
Mathematically,
where,
= constant velocity of rover = 2 m/s
= cosine function of angle 30°
Putting values in above equation, we get:
Hence, the horizontal velocity of rover is 1.73 m/s
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2.3275862×10¹²km/s fast is sirius moving in km/s.
<h3>Briefing:</h3>Hydrogen has a spectral line at = 116nm=116×10⁻⁹m
Line is observed at = 107 nm=107×10⁻⁹m
Now, from the Hubble's law
V=×C
Where,
v is the velocity
Δλ = Change in wavelength = 116 - 107= 9nm=9×10⁻⁹m
λ = Actual wavelength=116nm=116×10⁻⁹m
C is the speed of the light=3×10⁸m/s
on substituting the respective values, we get
V=(9/116)×3×10⁸=23275862.069×10⁵m/s
V=2.3275862×10¹²km/s.
<h3>What is the wavelength?</h3>A waveform signal's wavelength, which is the distance between two identical locations (adjacent crests) in the succeeding cycles, determines whether it is sent through space or via a wire. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
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Answer with Explanation:
We are given that
Fundamental frequency,f=88.4 Hz
Speed of sound,v=343 m/s
We have to find the first three overtones.
Tube is closed
The overtone of closed pipe is equal to odd number of fundamental frequency.
Therefore, the overtone of tuba
Where n=3,5,7,..
Substitute n=3
For second overtone
For third overtone
Answer:
L = 1.545 m
Explanation:
Let the total length of the rod is L
now the torque must applied on the other end of the rod so that it will balance the torque due to weight of rock on other side of fulcrum
so we will have
so we have
F = 663 N
Answer:
Explanation:
The total energy of the satellite when it is still in orbit is given by the formula
where
G is the gravitational constant
m = 525 kg is the mass of the satellite
is the Earth's mass
r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:
So the initial total energy is
When the satellite hits the ground, it is now on Earth's surface, so
so its gravitational potential energy is
And since it hits the ground with speed
it also has kinetic energy:
So the total energy when the satellite hits the ground is
So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite: