A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second.
2 answers:
<u>Answer:</u> The horizontal velocity of rover is 1.73 m/s
<u>Explanation:</u>
Horizontal velocity is defined as the velocity of body proceeding in the horizontal direction. This velocity proceeds in the 'x' direction.
Mathematically,
where,
= constant velocity of rover = 2 m/s
= cosine function of angle 30°
Putting values in above equation, we get:
Hence, the horizontal velocity of rover is 1.73 m/s
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The correct answer is :
Unit vectors I and j along the x-axis and y-axis, respectively, define the Cartesian coordinate system. The radial unit vector r, which indicates the direction from the origin, and the unit vector t, which is orthogonal (perpendicular) to the radial direction, together create the polar coordinate system.
We can obtain the horizontal component by applying the trigonometric identity of Cos(Ф), and if we obtain the component on the x axle, such as 22000 (m)×Cos(51°) = x, we may determine that x = 13845.05 metres. We need to obtain the vector components because we already know the distance and the angle.
To learn more about Cartesian unit-vector refer the link:
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