Question

A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second. Calculate its horizontal velocity.

Answer 1

Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.

Answer 2

Answer: The horizontal velocity of rover is 1.73 m/s

Explanation:

Horizontal velocity is defined as the velocity of body proceeding in the horizontal direction. This velocity proceeds in the 'x' direction.

Mathematically,

$V_x=V_o\cos \theta$

where,

$V_o$ = constant velocity of rover = 2 m/s

$\cos \theta$ = cosine function of angle 30°

Putting values in above equation, we get:

$V_x=2\times \cos (30^o)\\\\V_x=1.73m/s$

Hence, the horizontal velocity of rover is 1.73 m/s