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2 years ago

Conclusions _____.

Physics

1 answer:

PIT_PIT [208]2 years ago

5 0

Answer:

hjk

Explanation:

hjkhjk

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A baseball has a mass of 0.145 kilograms, and a bowling ball has a mass of 6.8 kilograms. What is the gravitational force betwee

Olegator [25]

Quite low

Gravitation force = $\frac{6.67* 10^{-11}*0.145*6.8 }{ 0.5^{2} }$ = 26.3 * $10^{-11}$ = 2.63 * $10^{-10}$ N

6 0

3 years ago

Read 2 more answers

Hannah walks 0.30 km to class in 5.0 min. what is her average speed in m/s?

OverLord2011 [107]

Answer:

1.0 m/s

Explanation:

First, convert to SI units.

0.30 km × (1000 m / km) = 300 m

5.0 min × (60 s / min) = 300 s

Speed is distance divided by time:

300 m / 300 s = 1.0 m/s

3 0

3 years ago

If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Mariana [72]

The kinetic energy of the phone right before it hits the ground is 9J.

<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

m is mass of the phone
v is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

7 0

2 years ago

A 45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦

Neko [114]

Answer:

v = 21.03 m/s

Explanation:

given,

mass of skier = 45 kg

the slope of the snow = 10.0◦

coefficient of friction = 0.114

distance traveled = 300 m

speed = ?

Acceleration = g sin θ - µ g Cos θ

= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)

= 0.737 m/s²

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 0.737 × 300

v = 21.03 m/s

Speed of skier's after travelling 300 m speed is equal to 21.03 m/s

6 0

3 years ago

In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation

mr_godi [17]

Answer:

the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

$W_{Demand} = W_{Supply}$

15 - (1/200) L = 5 + (1/200) L

15 - 5 = (1/200) L + (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0

3 years ago