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stiv31 [10]
3 years ago
15

What happens during meiosis1​

Chemistry
2 answers:
djyliett [7]3 years ago
6 0
In meiosis I, chromosomes in a diploid cell resegregate, producing four haploid daughter cells. It is this step in meiosis that generates genetic diversity. DNA replication precedes the start of meiosis I. During prophase I, homologous chromosomes pair and form synapses, a step unique to meiosis.
LuckyWell [14K]3 years ago
6 0

Answer:

Meiosis Tutorial

Meiosis I & II

What is meiosis I?

In meiosis I, chromosomes in a diploid cell desegregate, producing four haploid daughter cells. It is this step in meiosis that generates genetic diversity.

The phases of meiosis I & II

Prophase I

Prophase I  

DNA replication precedes the start of meiosis I. During prophase I, homologous chromosomes pair and form synapses, a step unique to meiosis. The paired chromosomes are called bivalents, and the formation of chiasmata caused by genetic recombination becomes apparent. Chromosomal condensation allows these to be viewed in the microscope. Note that the bivalent has two chromosomes and four chromatids, with one chromosome coming from each parent.

Prometaphase I

Prometaphase I  

The nuclear membrane disappears. One kinetochore forms per chromosome rather than one per chromatid, and the chromosomes attached to spindle fibers begin to move.

Metaphase I

Metaphase I  

Bivalents, each composed of two chromosomes (four chromatids) align at the metaphase plate. The orientation is random, with either parental homologue on a side. This means that there is a 50-50 chance for the daughter cells to get either the mother's or father's homologue for each chromosome.

Anaphase I

Anaphase I  

Chiasmata separate. Chromosomes, each with two chromatids, move to separate poles. Each of the daughter cells is now haploid (23 chromosomes), but each chromosome has two chromatids.

Telophase I

Telophase I  

Nuclear envelopes may reform, or the cell may quickly start meiosis II.

Cytokinesis

Cytokinesis  

Analogous to mitosis where two complete daughter cells form.

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How many acidic H+ ion is given by H3BO3 in aqueous solution?? ...?
notka56 [123]
Boric acid, H3BO3, in aqueous solution would only give out one H+ ion. As it is also produce OH ion and by hydrolysis it produces one proton. <span>All the boron compounds (BX3) are having only 6 valence electrons in it and should follow the octet rule by taking another electron.</span>
 
B(OH)3 + 2 H2O → B(OH)4− + H3O
7 0
3 years ago
When 3.4 moles of hydrogen gas react with excess oxygen how many moles of water will be produced
s344n2d4d5 [400]
1. start with balanced equation.
2 H2(g) + O2(g<span>) </span><span> 2 H</span>2O(g<span>)
</span>
2. Use stoichiometry 
(3.4moles of H)(2moles of H2O/2moles of H)
The moles of H will cancel, leaving you with moles of H2O. 
The answer is 3.4 moles of H2O
6 0
4 years ago
If the mass is 100g and the density is 0.8g/ml what is the volume
borishaifa [10]
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6 0
3 years ago
_Cuo +H, → _Cu + _H,0
Elena-2011 [213]
<h3>Answer:</h3>

CuO(s) + H₂(g) →  Cu(s) + H₂O(l)

<h3>Explanation:</h3>
  • Assuming the reaction is the reduction of CuO by H₂
  • Then the balanced equation for the reaction is;

CuO(s) + H₂(g) →  Cu(s) + H₂O(l)

  • The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
  • The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.
  • In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.

3 0
3 years ago
From a laboratory process, a student collects 28.0 g of hydrogen and 224.0 g of oxygen. how much water was originally involved i
nikklg [1K]

Chemical reaction is given as :

2H_{2}O\rightarrow 2H_{2}+O_{2}

Here, 2 moles of water gives 2 moles of hydrogen and one mole of oxygen.

Mass of hydrogen =  28.0 g (given)

Mass of oxygen = 224.0 g (given)

Number of moles = \frac{given mass}{molar mass}

Thus, number of moles of hydrogen = \frac{28 g}{2\times 1 g/mol}

= 14 moles of hydrogen

Number of moles of oxygen= \frac{224 g}{2\times 16 g/mol}

= 7 moles of oxygen

Now, to find the amount of water:

7 mol of oxygen \times (\frac{2 mol of water}{1 mol of oxygen})\times (18 g/mol of water)

= 252 g of water.

Thus, amount of water is 252 g (involved in the process).






4 0
4 years ago
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