Answer:
13
Explanation:
Let's consider the unbalanced equation for the combustion of propane.
C₃H₈ + O₂ ⇒ CO₂ + H₂O
We will begin balancing H atoms by multiplying H₂O by 4.
C₃H₈ + O₂ ⇒ CO₂ + 4 H₂O
Now, we balance C atoms by multiplying CO₂ by 3.
C₃H₈ + O₂ ⇒ 3 CO₂ + 4 H₂O
Finally, we get the balanced equation multiplying O₂ by 5.
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
The sum of the coefficients is 1 + 5 + 3 + 4 = 13.
<em>Hey</em><em>!</em><em>!</em>
<em>Here</em><em>'s</em><em> </em><em>your</em><em> </em><em>answer</em>
<em>Thermal</em><em> </em><em>energy</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>energy</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>generated</em><em> </em><em>or</em><em> </em><em>measured</em><em> </em><em>by</em><em> </em><em>heat</em><em>.</em>
<em>Thermal</em><em> </em><em>en</em><em>ergy</em><em> </em><em>measures</em><em> </em><em>the</em><em> </em><em>movement</em><em> </em><em>of</em><em> </em><em>atoms</em><em> </em><em>or</em><em> </em><em>molecules</em><em> </em><em>within</em><em> </em><em>a</em><em> </em><em>substance</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
Determining if an object will float or sink is based on the density of the object and also the density of the solution, the lower the density, more likely the object is to float, and if the density is higher, therefore the object is heavier and it will sink. In our question we have ebony wood with a density of 1.2, the only possible layer that this material can float is on Chloroform, that has a higher density, therefore the answer is letter A
Answer:
Limiting reactant is NiSO₄
Explanation:
The reaction of aluminum metal with aqueous nickel(II) sulfate to produce aqueous aluminum sulfate and nickel is:
2 Al(s) + 3 NiSO₄ → Al₂(SO₄)₃ + 3 Ni
<em>That means 2 moles of Al react with 3 moles of nickel sulfate.</em>
<em />
Moles of Al and NiSO₄ are:
Al: 108g × (1mol / 26.98g) = 4.00 moles of Al
NiSO₄: 464g × (1mol / 154.75g) = 3.00 moles of NiSO₄
For a complete reaction of aluminium there are necessary:
4.00mol Al ₓ ( 3 moles NiSO₄ / 2 moles Al) = 6 moles of NiSO₄
As you have just 3.00 moles of NiSO₄, the <em>limiting reactant is NiSO₄</em>
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:
Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:
To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=