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Sergio [31]
3 years ago
14

Help for brainliest!

Physics
1 answer:
madam [21]3 years ago
3 0

A “real” image occurs when light rays actually intersect at the image, and become inverted, or turned upside down. ... In flat, or plane mirrors, the image is a virtual image, and is the same distance behind the mirror as the object is in front of the mirror. The image is also the same size as the object.

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En el diseño de una sesión de aprendizaje, la profesora Patricia, tiene como propósito de aprendizaje: Aplica sus habilidades mo
Leviafan [203]

Answer:

im in hardvard dont cheat get amzing grades if you want to go here

Explanation:

5 0
3 years ago
An electromagnetic wave of intensity 150 W/m2 is incident normally on a rectangular black card with sides of 25 cm and 30 cm tha
LenKa [72]

Answer:

3.75 × 10⁻⁸ N

Explanation:

Given:

Intensity of the electromagnetic wave, I = 150 W/m²

Sides of the board = 25 cm (= 0.25 m) and 30 cm (= 0.30 m)

therefore,

the area of the rectangular box, A = 0.25 × 0.30 = 0.075 m²

Now,

force exerted on the card by the radiation, F = \frac{IA}{C}

here,

C is the speed of the light = 3 × 10⁸ m/s

on substituting the respective values, we get

F = \frac{150\times0.075}{3\times10^8}

or

F = 3.75 × 10⁻⁸ N

5 0
3 years ago
A particle executes simple harmonic motion with an amplitude of 2.18 cm.
Bogdan [553]

Answer:

The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.

Explanation:

Maximum speed is  :

                          v (max) = Aω

Speed v at any displacement y is given by  

v^{2} = w^{2} (A^{2} - y^{2})   ........................................................  i

And,

               v = \frac{1}{2} v (max)  

          or,  2 × v = Aω     ....................................................   ii

Eliminating  ω from equations i and ii,

                       \frac{1}{4} A^{2}  w^{2}  =  w^{2}  ( A^{2}  - y^{2})

                     or, y^{2} =  (\frac{3}{4}) A^{2}  =(\frac{3}{4}) 2.18^{2}

                    or,  y =  3.56 cm.

3 0
3 years ago
an electron, a proton and a deuteron move in a magnetic field with same momentum perpendicularly. the ratio of the radii of thei
wel

If an electron, a proton, and a deuteron move in a magnetic field with the same momentum perpendicularly, the ratio of the radii of their circular paths will be:

  • 1: √2 : 1

<h3>How is the ratio of the perpendicular parts obtained?</h3>

To obtain the ratio of the perpendicular parts, one begins bdy noting that the mass of the proton = 1m, the mass of deuteron = 2m, and the mass of the alpha particle  = 4m.

The ratio of the radii of the parts can be obtained by finding the root of the masses and dividing this by the charge. When the coefficients are substituted into the formula, we will have:

r = √m/e : √2m/e : √4m/2e

When resolved, the resulting ratios will be:

1: √2 : 1

Learn more about the radii of their circular paths here:

brainly.com/question/16816166

#SPJ4

​

6 0
2 years ago
An automobile with passengers has weight 19.4 kN and is moving at 108 km/h when the driver brakes to a stop. The frictional forc
mixer [17]

Answer:

12.0

Explanation:

4 0
3 years ago
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