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Masja [62]
3 years ago
7

Which two compounds are molecules which both contain a double bond

Chemistry
1 answer:
Mademuasel [1]3 years ago
7 0

Answer:

Double bond

Chemical compounds with double bonds.

Ethylene Carbon-carbon double bond.

Acetone Carbon-oxygen double bond.

Dimethyl sulfoxide Sulfur-oxygen double bond.

Diazene Nitrogen-nitrogen double bond.

Explanation:

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Which has a geographic North Pole and South Pole?
Bogdan [553]

Answer:

A. Earth only

Explanation:

The Earth rotates on the geographic north and south poles. The geographic north and south poles are where lines of longitude (meridians) converge in the north. On the other side of the Earth, the South Pole lies on a continental land mass known as Antarctica.

plz mark me as brainliest :)

7 0
3 years ago
Read 2 more answers
Acceleration is defined as the rate of change for which characteristic?
weeeeeb [17]

Answer:

Acceleration is defined as the rate of change for velocity.

4 0
4 years ago
How many grams of oxygen are required to burn 60 grams of ethane gas, C2H6? 2 C2H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H2O (g)
timofeeve [1]
60 g C2H6 × 1 mol C2H6 x   7 mol O2     x     32 g O2   =      ~223.5 g O2
                        30.068 g      2 mol C2H6        1 mol O2
8 0
3 years ago
C10H12O4S(s) + O2(g)  CO2(g) + SO2(g) + H2O(g)
ale4655 [162]

Answer: The coefficient for O_2(g) is 12.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

C_{10}H_{12}O_4S(s)+12O_2(g)\rightarrow 10CO_2(g)+SO_2(g)+6H_2O

Thus in the reactants, there are 12 molecules of oxygen in balanced chemical equation. Thus the coefficient for O_2(g) is 12.

8 0
3 years ago
A metal ion Mⁿ⁺ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 2.961 x 10¹⁶ Hz
Whitepunk [10]

Answer:

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

Explanation:

First of all

v=f*λ

In our case v=c

c=f*λ

λ=c/f

where:

c is the speed of light

f is the frequency

\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m

Using Rydberg's Formula:

\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})

Where:

R is Rydberg constant=1.097*10^7

z is atomic Number

For highest Energy:

n_1=1

n_2=∞

\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99

z≅3

Atomic number is 3, So ion is Lithium ion (Li^+)

3 0
3 years ago
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