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Ede4ka [16]
3 years ago
9

Question 9 (1 point)

Chemistry
1 answer:
Juliette [100K]3 years ago
7 0

Noble gases

Explanation:

     Electronic configuration 1s²  2s²   2p⁶

 The element belongs to the group of the noble gases.

  • The noble gases have complete outer shell configuration of their atoms.
  • we can infer that the configuration above is for an element in the p-block because the last sub-level filled is the p-orbital.
  • The elements therefore belongs to the p-block
  • The block is from group 111A to O
  • Only the halogens and noble gases fits this picture from the option.
  • The outer most p-subshell have three orbitals requiring 6 electrons to fill them up.
  • This makes a complete and stable configuration.
  • The highest energy level of 2 is also made up of 8 electrons, an octet.
  • This is why we can conclude that they are noble gases.

Learn more:

Noble gas brainly.com/question/1781595

#learnwithBrainly

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Answer:

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Name for continents in one landmass surrounded by gigantic ocean
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How are Celsius, Kelvin, and Fahrenheit scales similar? How are they different? Considering their differences, think of one scen
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3 years ago
A balloon contains 0.15 moles of co2 gas. how many molecules of co2 are in the balloon?
Sauron [17]
1- One mole is = 6.02 x 10^23 of anything, So one mole of atoms is 6.02x10^23.

2- when the balloon contains 0.15 moles of Co2 gas so:

the no.of molecules of Co2 = 0.15 x 6.02x 10^23

                                              = 9.0 x 10^22
5 0
3 years ago
Read 2 more answers
Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be
mylen [45]

yield = 52.23 %

Explanation:

We have the following chemical reaction:

2 Al (s) + 2 KOH (aq) + 4 H₂SO₄ (aq) + 10 H₂O → 2 KAl(SO₄)₂·12 (H₂O) (s) + 3 H₂ (g)

mass of aluminium = mass of bottle with aluminium pieces - bottle mass

mass of aluminium = 10.8955 - 9.8981 = 0.9974 g

mass of alum = mass of bottle with final product - bottle mass

mass of alum = 19.0414 - 9.8981 = 9.1433 g

number of moles = mass / molecular weight

number of moles of aluminium = 0.9974 / 27 = 0.03694 moles

number of moles of alum (practical) = 9.1433 / 474 = 0.01929 moles

To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if       2 moles of aluminium produce 2 moles of alum

then 0.03694 moles of aluminium produce X moles of alum

X = (0.03694 × 2) / 2 = 0.03694 moles of alum (theoretical)

yield = (practical quantity / theoretical quantity) × 100

yield = (0.01929 /  0.03694) × 100

yield = 52.23 %

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reaction yield

brainly.com/question/7786567

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5 0
3 years ago
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