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hammer [34]
3 years ago
12

If f(×) =

ac{1}{ \sqrt{x - 1} } " alt=" \frac{1}{ \sqrt{x - 1} } " align="absmiddle" class="latex-formula">
then find \frac{f(x) - f(2)}{x - 2}
​
Mathematics
1 answer:
Kamila [148]3 years ago
8 0

9514 1404 393

Answer:

  (1 -x +√(x -1))/(x² -3x +2)

Step-by-step explanation:

Fill in the given function definition and simplify.

  \dfrac{f(x)-f(2)}{x-2}=\dfrac{\dfrac{1}{\sqrt{x-1}}-\dfrac{1}{\sqrt{2-1}}}{x-2}=\dfrac{1-\sqrt{x-1}}{(x-2)\sqrt{x-1}}\\\\=\dfrac{\sqrt{x-1}-x+1}{(x-2)(x-1)}=\boxed{\dfrac{\sqrt{x-1}-x+1}{x^2-3x+2}}

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What is the y- intercept of the function described in the table x: 1,2,3,4 y: 8,6,4,2
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Answer:

The y-intercept of the function is: b=10

Step-by-step explanation:

Given the table

x                 y

1                 8

2                6

3                4

4                2

Taking any two points to find the slope

  • (1, 8)
  • (2, 6)

The slope between (1, 8) and (2, 6) is:

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(1,\:8\right),\:\left(x_2,\:y_2\right)=\left(2,\:6\right)

m=\frac{6-8}{2-1}

m=-2

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Substituting m=-2 and any point i.e. (1, 8) in the slope-intercept form of the line equation to find the y-intercept (b).

y=mx+b

8 = -2(1) + b

8 = -2 + b

b = 8+2

b = 10

Thus, the y-intercept of the function is: b=10

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