Answer:
760 mmHg
Explanation:
Step 1: Given data
- Partial pressure of nitrogen (pN₂): 592 mmHg
- Partial pressure of oxygen (pO₂): 160 mmHg
- Partial pressure of argon (pAr): 7 mmHg
- Partial pressure of the trace gas (pt): 1 mmHg
Step 2: Calculate the atmospheric pressure
Since air is a gaseous mixture, the atmospheric pressure is equal to the sum of the gases that compose it.
P = pN₂ + pO₂ + pAr + pt = 592 mmHg + 160 mmHg + 7 mmHg + 1 mmHg = 760 mmHg
They are gases at room temperature
Hope this helps:)
Answer:
use n=m/M (moles=mass/molar mass) to find out how many moles of C2H6 there are in 60g
Explanation:
23.01 g of zinc (Zn)
Explanation:
We have the following chemical reaction:
3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂
number of moles = mass / molar weight
number of moles of phosphoric acid = 23.1 / 98 = 0.236 moles
Taking in account the chemical reaction, we devise the following reasoning:
if 2 moles of H₃PO₄ are reacting with 3 moles of Zn
then 0.236 moles of H₃PO₄ are reacting with X moles of Zn
X = (0.236 × 3) / 2 = 0.354 moles of Zn
mass = number of moles × molar weight
mass of Zn = 0.354 × 65 = 23.01 g
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number of moles
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