A crucible is a severe test or trial. It is also a vessel in which materials are melted at high temperatures to produce a more r
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Answer:
.
One chlorine molecule reacts with two formula units of (aqueous) potassium bromide to produce one bromine molecule and two formula units of (aqueous) potassium chloride.
Explanation:
<h3>Formula for each of the species</h3>Start by finding the formula for each of the compound.
- Both chlorine
and bromine
are group 17 elements (halogens.) Each
- On the other hand, potassium
is a group 1 element (alkaline metal.) Each
Therefore, the ratio between atoms and
atoms in potassium bromide is supposed to be one-to-one. That corresponds to the empirical formula
. Similarly, the ratio between
The formula for chlorine gas is , while the formula for bromine gas is
.
Write down the equation using these chemical formulas.
.
Start by assuming that the coefficient of compound with the largest number of elements is one. In this particular equation, both and
features two elements each.
Assume that the coefficient of is one. Hence:
.
Note that is the only source of
and
atoms among the reactants of this reaction.
There would thus be one atom and one
atom on the reactant side of the equation.
Because atoms are conserved in a chemical equation, there should be the same number of and
atoms on the product side of the equation.
In this reaction, is the only product with
atoms.
One atom would correspond to
units of
.
Similarly, in this reaction, is the only product with
atoms.
One atom would correspond to one formula unit of
.
Hence:
.
Similarly, there should be exactly one atom on either side of this equation. The coefficient of
should thus be
. Hence:
.
That does not meet the requirements, because two of these coefficients are not integers. Multiply all these coefficients by two (the least common multiple- LCM- of these two denominators) to obtain:
.
Answer:
Samira's model is incorrect because not all atoms are accounted for
Explanation:
The image of Samira's model has been attached to this answer to enhance the explanation.
What is depicted in that model is rightly regarded as a chemical change. In a chemical change atoms of substances are rearranged as new substances are formed.
However, all atoms in the products must also be found in at least one of the reactants. In this case we have an atom in one of the products that is not accounted for. Hence the model is incorrect.
Answer:
95.6 %
Explanation:
For this question, we will have <u>2 reactions</u>, the formation of the <u>grignard reagent</u> and the <u>formation of the alcohol</u>. The first step then is the calculation of the <u>maximum amount</u> of the grignard reagent. For this, we have to convert the grams to moles and check the smallest value. To do this we have to take into account the <u>following conversion ratios</u>:
Molar mass of Mg = 24 g/mol
Molar mass of phenylmagnesium bromide ()= 157 g/mol
Density of bromobenzene= 1.5 g/mL
Molar ratio between Mg and = 1:1
The smallest value is the mol of bromobenzene therefore <u>0.0402 mol</u> of phenylmagnesium bromide would be produced.
The next step is repite the same steps for the reaction of <u>formation of the alcohol</u>. Therefore we have to find the moles of methyl benzoate, so:
Molar mass of methyl benzoate: 136.14 g/mol
The we have to <u>divide by the coefficient</u> of each reactive in the balance reaction. So:
Therefore the <u>limiting reagent</u> would be the phenylmagnesium bromide. Now, the <u>molar ratio</u> between the phenylmagnesium bromide and triphenyl carbinol is <u>2:1</u>, so the amount of alcohol produced is 0.0201 mol triphenyl carbinol. The next step is the conversion from mol to <u>grams of triphenyl carbinol</u>:
Molar mass of triphenyl carbinol= 260.33 g/mol
Finally, we have to <u>divide</u> the obtanied solid by the calculated one:
