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Oksi-84 [34.3K]
3 years ago
10

Cela est it possible ?

Physics
1 answer:
Ede4ka [16]3 years ago
8 0
I’m sorry can’t helpless
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it does use it at doppler

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My dad told me the hes a cop so yw

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Which statement BEST describes the benefits of muscular fitness training?
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Whatever the statement is, I know one thing for sure:  It's NOT included on the list of choices that you've provided.

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Express 0.00000000062 kg in scientific notation. 6.2 x 1010kg 6.2 x 10-10kg 0.62 x 10-9kg
PilotLPTM [1.2K]
I believe the correct answer from the choices listed above is the second option. The scientific notation of the measurement 0.00000000062 kg would be <span>6.2 x 10^-10 kg. Scientific notation is used to express too large and too small values of numbers. Hope this helps. Have a nice day.</span>
7 0
2 years ago
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Hooke's law. The distance d when a spring is stretched by a hanging objective varies directly as the weight w of the object. If
Fofino [41]
<span>Hooke's law is F=-kx, which means the elastic force contained by the spring is a product of the distance it stretches and its spring constant, but the direction of the force is opposite that of the displacement. We calculate as follows:

</span><span>(3 kg)(9.8 m/s^2) = -k(-0.38 m)
</span>k =<span> 77.4

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7 0
3 years ago
The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

   R = 1 AU = 1.496 × 10¹¹ m

   M = 2.3 × 10³⁰ kg

Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

Approximate escape speed = 45.3 km/s

6 0
3 years ago
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