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2 years ago

Evidence on why we don’t hear solar eruptions on Earth.

Physics

2 answers:

sukhopar [10]2 years ago

8 0

Because sound waves don't travel through the vaccume of space. Hope this helped

8_murik_8 [283]2 years ago

5 0

I can’t give five but I know on reason why if we could hear them it would be extremely loud evidence is that a scientist called Scott Mclntosh of the national center for atmospheric research (tip: if we could hear it from earth we would probs go deaf too)

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a 12.0L container is filled with a gas to a pressure of 2660 torr at 0°C. At what temp. will the pressure inside the container b

Alexxx [7]

$\frac{p1}{t1} = \frac{p2}{t2}$

Pressure Law: constant volume

Convert all Temperatures to Kelvin

0°C= 273K

$\frac{2660}{273} = \frac{3040}{t2} \\ \\ 3040 \times 273 = t2 \times 2660 \\ \\ 829920 \div 2660 = t2 \\ \\ t2 = 312$

answer= 312Kelvin

6 0

3 years ago

A man jumps from a 45 m cliff into a large body of water. How long will he fall before he enters the wate

julia-pushkina [17]

Answer:

about 2.5 seconds depending on if he jumps up and out or if he jumps out.

Explanation:

7 0

2 years ago

Consider two insulating balls with evenly distributed equal and opposite charges on their surfaces, held with a certain distance

siniylev [52]

Answer:

interest point:

1) Point on the left side

2) Point within the radius r₁ of the first sphere

3) Point between the two spheres

4) point within the radius r₂ of the second sphere

5) Right side point

Explanation:

In this case, the total electric field is the vector sum of the electric fields of each sphere, to simplify the calculation on the line that joins the two spheres

We will call the sphere on the left 1 and it has a positive charge Q with radius r1, the sphere on the right is called 2 with charge -Q with radius r2. The total field is

E_ {total} = E₁ + E₂

E_{ total} = $k \frac{Q}{x_1^2} + k \frac{Q}{x_2^2}$

the bold indicate vectors, where x₁ and x₂ are the distances from the center of each sphere. If the distance that separates the two spheres is d

x₂ = x₁ -d

E total = $k \frac{Q}{x_1^2} - k \frac{Q}{(x_1 - d)^2}$

Let's analyze the field for various points of interest.

1) Point on the left side

in this case

E_ {total} = $k Q \ ( \frac{1}{x_1^2} - \frac{1}{(x_1 +d)2} )$

E_ {total} = $k \frac{Q}{x_1^2}$ $( 1 - \frac{1}{(1 + \frac{d}{x_1} )^2 } )$

We have several interesting possibilities:

* We can see that as the point is further away the field is more similar to the field created by two point charges

* there is a point where the field is zero

E_ {total} = 0

x₁² = (x₁ + d)²

2) Point within the radius r₁ of the first sphere.

In this case, according to Gauus' law, the charge is on the surface of the sphere at the point, there is no charge inside so this sphere has no electric field on its inner point

E_ {total} = $-k \frac{Q}{x_2^2} = -k \frac{Q}{((d-x_1)^2}$

this expression holds for the points located at

-r₁ <x₁ <r₁

3) Point between the two spheres

E_ {total} = $k \frac{Q}{x_1^2} + k \frac{Q}{(d+x_1)^2}$

This champ is always different from zero

4) point within the radius r₂ of the second sphere, as there is no charge inside, only the first sphere contributes

E_ {total} = $+ k \frac{Q}{(d-x_1)^2}$ + k Q / (d-x1) 2

point range

-r₂ <x₂ <r₂

5) Right side point

E_ {total} = $k \frac{Q}{(x_2-d)^2} - k \frac{Q}{x_2^2}$

E_ {total} = $- k \frac{Q}{x_2^2} ( 1- \frac{1}{(1- \frac{d}{x_2})^2 } )$ - k Q / x22 (1- 1 / (x1 + d) 2)

we have two possibilities

* as the distance increases the field looks more like the field created by two point charges

* there is a point where the field is zero

8 0

2 years ago

Both lead and zinc are formed as precipitates. Which of these is a step in the formation of the minerals?

Ahat [919]

Minerals are naturally occurring inorganic (they're not formed from amino acids, peptides, or enzymes) chemical compounds.

From the given options, the following describes a step in the formation of the minerals: materials break up due to rise in temperature.

Correct answer: D

5 0

3 years ago

A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0 and then along the y axis from y = 0 to y

Rashid [163]

Answer: F = 2N

Explanation: If a current i is flowing in a wire of length L lying in a region of magnetic field B, then the magnetic force acting on the wire is given by

F = BIL

Please find the attached file for the solution

8 0

2 years ago