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3 years ago

Which planet will take the shortest revolution around the sun?

2 answers:

6 0

MERCURY is the all-around winner.

It's the planet closest to the sun. It has the fastest orbital speed,
the shortest distance to go, and the shortest period of revolution.

LUCKY_DIMON [66]3 years ago

3 0

The planet closest to the sun; Mercury.

You might be interested in

Iodine 131 half life is 8.0 days. Ten percent of the original sample o his isotope remains after (a) 22.7 days (b) 24.9 days (c)

Artyom0805 [142]

Answer:

option (c) is correct

Explanation:

Half life of a substance is the time in which the element becomes half of is initial value.

half life, T = 8 days

Amount remaining, N = 10 % of original value

Let the original value is No.

N = 10% of No

N = 0.1 No

Let the time taken is t and the decay constant is λ.

The relation between the decay constant and the half life is given by

$\lambda =\frac{0.6931}{T}=\frac{0.6931}{8}=0.08664 per day$

Us the equation of radioactivity

$N=N_{0}e^{-\lambda t}$

$0.1N_{0}=N_{0}e^{-0.08664 t}$

$e^{0.08664 t}=10$

Taking natural log on both the sides, we get

0.08664 t = 2.303

t = 26.6 days

4 0

3 years ago

Could I please get some help l, will mark as Brianalist if right....

miss Akunina [59]

Answer:

Option 2

Explanation:

Weight of the box is being acted downwards due to gravity

However, based on Newton's third law (for every action (force) in nature there is an equal and opposite reaction), an equal force will act on the box by the table

8 0

2 years ago

Read 2 more answers

What will be the value of both charges if they are 5 cm apart and suffer a

Mrac [35]

Answer:

$\boxed{q = 1.2 \times {10}^{ - 6} C}$

Explanation:

$f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6}$

3 0

2 years ago

2.- Si una cámara fotográfica emite un pulso de sonido para enfocar un objeto, determinar

uranmaximum [27]

Answer:

a. El tiempo de recorrido es $5.882\times 10^{-3}$ segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

Explanation:

El sonido es un tipo de onda mecánica, que es un tipo de onda que necesita de un medio material para propagarse. En este caso, entendemos que el sonido se propaga a través del aire atmosférico hasta llegar a su destino y devolverse a rapidez constante. Entonces, podemos estimar el tiempo ( $t$ ), medido en segundos, a partir de la siguiente fórmula:

$t = \frac{2\cdot x_{s}}{v_{s}}$

Donde:

$x_{s}$ - Distancia entre la cámara fotográfica y el objeto, medida en metros.

$v_{s}$ - Rapidez del sonido en el aire atmosférico, medida en metros por segundo.

A continuación, calculamos el tiempo de recorrido:

a. ( $x_{s} = 1\,m$ , $v_{s} = 340\,\frac{m}{s}$ )

$t = \frac{2\cdot (1\,m)}{340\,\frac{m}{s} }$

$t = 5.882\times 10^{-3}\,s$

El tiempo de recorrido es $5.882\times 10^{-3}$ segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

b. ( $x_{s} = 20\,m$ , $v_{s} = 340\,\frac{m}{s}$ )

$t = \frac{2\cdot (20\,m)}{340\,\frac{m}{s} }$

$t = 0.118\,s$

El tiempo de recorrido es 0.118 segundos para un objeto localizado a un metro de distancia de la cámara fotográfica.

8 0

3 years ago

The _____ of a wave is the number of wave cycles per second. this quantity is given the symbol ν and has units of s–1 or _____.

Fynjy0 [20]

The frequency of a wave is the number of wave cycles per second. this quantity is given the symbol ν and has units of s^–1 or hertz.

What is a wave ?

A wave is a dynamic disturbance of one or more quantities that propagates through time. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.

What is a wave cycle ?

The wavelength is the measured distance in meters between two waves' peaks or troughs, which is referred to as a wave cycle. It's crucial to remember that the distance from peak to peak equals the distance from trough to trough. The length of time it takes a wave to complete one cycle is known as the wave's period.

Learn more about waves here:-

brainly.com/question/3639648

#SPJ4

8 0

1 year ago